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3 years ago

A conductor is a material in which what can move through easily? Electrons Water Condensation Oil

Physics

1 answer:

kondaur [170]3 years ago

4 0

Answer:

Electrons

Explanation:

:) hope this helps. Have a great day!

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The diagram shows the movement of air as a result of convection currents. At which point is the air at its highest density?

Gnesinka [82]

Hot air rises = it's less dense than cold air = falls

3 0

3 years ago

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A 7.75-l flask contains 0.482 g of hydrogen gas and 4.98 g of oxygen gas at 65°c. What is the partial pressure of oxygen in the

dimulka [17.4K]

Answer:

0.558 atm

Explanation:

We must first consider that both gases behaves like ideal gases, so we can use the following formula: PV=nRT

Then, we should consider that, whithin a mixture of gases, the total pressure is the sum of the partial pressure of each gas:

P₀ = P₁ + P₂ + ....

P₀= total pressure

P₁=P₂= is the partial pressure of each gass

If we can consider that each gas is an ideal gas, then:

P₀= (nRT/V)₁ + (nRT/V)₂ +..

Considering the molecular mass of O₂:

M O₂= 32 g/mol

And also:

R= ideal gas constant= 0.082 Lt*atm/K*mol

T= 65°C=338 K

4.98 g O₂ = 0.156 moles O₂

V= 7.75 Lt

Then:

P°O₂=partial pressure of oxygen gas= (0.156x0.082x338)/7.75

P°O₂= 0.558 atm

3 0

4 years ago

make a list of different types of energy sources found in our surroundings and categorize them into different form of energy.

MrRa [10]

Answer:

hdcygcyh

Explanation:

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3 years ago

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Beginning 145 miles directly south of the city of Hartville, a car travels due west. If the car is travelling at a speed of 42 m

ziro4ka [17]

Answer:

The rate of change of the distance is 14.89.

Explanation:

Given that,

Distance = 145 miles

Speed of car = 42 miles/hr

Distance covered by car = 55 miles

We need to calculate the the rate of change of the distance

According to figure,

Let OA is x, and AB is y.

Now, using Pythagorean theorem

$x^2=y^2+145^2$

On differentiating

$2x\dfrac{dx}{dt}=2y\dfrac{dy}{dt}$

$\dfrac{dx}{dt}=\dfrac{y}{x}\dfrac{dy}{dt}$

$\dfrac{dx}{dt}=\dfrac{55\times42}{\sqrt{55^2+145^2}}$

$\dfrac{dx}{dt}=14.89\ miles/hr$

Hence, The rate of change of the distance is 14.89.

8 0

3 years ago

A rigid tank contains air at a pressure of 70 psia and a temperature of 55 ˚F. By how much will the pressure increase as the tem

Katyanochek1 [597]

Answer:

P_2 = 62.69 psi

Explanation:

given,

P₁ = 70 psia T₁ = 55° F = (55 + 459.67) R

P₂ = ? T₂ = 115° F = (115 + 459.67) R

we know,

p = ρ RT

ρ is the density which is constant

R is also constant

now,

$\dfrac{P_2}{P_1} =\dfrac{T_2}{T_1}$

$\dfrac{P_2}{70} =\dfrac{55+459.67}{115+459.67}$

P_2 = 62.69 psi

Hence, the increase in Pressure is equal to P_2 = 62.69 psi

7 0

3 years ago