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Reptile [31]
3 years ago
15

Give an example of how the apparent motion of an object depends on the observers motion

Physics
1 answer:
QveST [7]3 years ago
7 0
In a moving car the outside looks to be moving. however if viewed from the outside, the car appears to be moving. so motion is relative to the person observing.
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A bullet is fired horizontally at a height of 1.3 meters and a velocity of 950 m/s. How long was the bullet in the air?
seropon [69]

Answer:

<em>The bullet was 0.52 seconds in the air.</em>

Explanation:

<u>Horizontal Motion </u>

It occurs when an object is thrown horizontally with a speed v from a height h.

The object describes a curved path ruled exclusively by gravity until it hits the ground.

To calculate the time the object takes to hit the ground, we use the following equation:

\displaystyle t=\sqrt{\frac{2y}{g}}

Note it doesn't depend on the initial velocity but on the height.

The bullet is fired horizontally at h=1.3 m, thus:

\displaystyle t=\sqrt{\frac{2\cdot 1.3}{9.8}}

\displaystyle t=\sqrt{\frac{2.6}{9.8}}

t = 0.52 s

The bullet was 0.52 seconds in the air.

3 0
3 years ago
What horizontal force is required to drag a 15.8 kg block a long a horizontal surface with a coefficient of friction of 0.3, at
nirvana33 [79]

Answer:

Explanation:your mom!

8 0
3 years ago
What material would make the best light bulb filament?
DanielleElmas [232]
The answer is B ! As in light bulb tungsten is working as resistor !
7 0
3 years ago
Read 2 more answers
The a992 steel rod bc has a diameter of 50 mm and is used as a strut to support the beam. determine the maximum intensity w of t
EastWind [94]

Answer:

w = 11.211 KN/m

Explanation:

Given:

diameter, d = 50 mm

F.S = 2

L = 3

Due to symmetry, we have:

Ay = By = \frac{w * 6}{2} = 3w

P_c_r = 3w * F.S = 3w * 2.0 = 6w

I = \frac{\pi}{64} (0.05)^4 = 3.067*10^-^7

To find the maximum intensity, w, let's take the Pcr formula, we have:

P_c_r = \frac{\pi^2 E I}{(KL)^2}

Let's take k = 1

E = 200*10^9

Substituting figures, we have:

6w = \frac{\pi^2 * 200*10^9 * 3.067*10^-^7}{(1 * 3)^2}

Solving for w, we have:

w = \frac{67266.84}{6}

w = 11211.14 N/m = 11.211 KN/m

Since Area, A= pi * (0.05)²

\sigma _c_r = \frac{w}{A}

\sigma _c_r = \frac{11.211}{\pi (0.05)^2} = 1.4 MPA < \sigma y. This means it is safe

The maximum intensity w = 11.211KN/m

3 0
3 years ago
An empty water tank has a rectangular base with side lengths of 1.2 m and 2.3 m. The weight of the tank applies a pressure of 35
LekaFEV [45]

Answer:

Weight = 966 Newton.

Explanation:

Given the following data;

Length = 1.2 m

Width = 2.3 m

Pressure = 350 Pa

To find the weight of the tank;

We know that weight is the force of gravity acting on an object multiplied by its mass.

Weight = mg = force

Hence, we would determine the force using the parameters that were given.

But we would first determine the area of the rectangular tank.

Area of rectangle, A = length * width

A = 1.2 * 2.3

A = 2.76 m²

Mathematically, pressure is given by the formula;

Pressure = force/area

Force = pressure * area

Substituting into the formula, we have;

Force = 2.76 * 350

Force = 966 Newton

Therefore, the weight of the tank is 966 Newton.

5 0
3 years ago
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