Answer:
Each student ticket costs $8.33
Each adult ticket costs $15.34
Step-by-step explanation:
At Niagra High, Mr. Borton bought 4 student tickets and 2 adult tickets for the high school musical which cost $64. then Mrs. Gelvoria bought 3 student tickets and 3 adult tickets for the show and it cost her $72. How much are each type of tickets?
s = cost of each student ticket
a = cost of adult ticket
Our system of equations:
4s + 2a = 64
3s + 3a = 71
-3(4s + 2a = 64) ==> -12s - 6a = -192
2(3s + 3a = 71) ==> 6s + 6a = 142
-12s - 6a = -192
6s + 6a = 142
-6s = -50
/-6 /-6
s = $8.33 (the cost of each student ticket)
Now, let's find the cost of each adult ticket:
4s + 2a = 64
4(8.33) + 2a = 64
33.32 + 2a = 64
-33.32 -33.32
2a = 30.68
/2 /2
a = 15.34 (the cost of each adult ticket)
(x, y) ==> (8.33, 15.34)
Check your answer:
4s + 2a = 64
4(8.33) + 2(15.34) = 64
33.32 + 30.68 = 64
64 = 64
This statement is true
Hope this helps!
Answer:
x ≤ 75
Step-by-step explanation:
The computation of the inequality function is as follows:
Let us assume the remaining time left for other drills be x
Given that the team spends 20 minutes for running laps
And minimum of 15 minutes for discussing plays
Also practicing for last one hour and 45 minutes
Now as we know that
1 hour = 60 minutes
So total minutes would be
= 60 + 45
= 105 minutes
Total minutes spend by the team is
= 20 + 15
= 35 minutes
So now the remaining time left is
x ≤ 105 - 35
x ≤ 75
Answer:
6x+5y
Step-by-step explanation:
Combining like terms (x and y)
we get
30x-24x=6x
6y-y=5y
=> 6x+5y
Answer:
looks like D! Have a nice day :D
Answer:
250ft
Step-by-step explanation:
45ft + 45ft of fencing for the two short ends. 80ft +80ft for the two long sides
45ft+45ft=90ft
80ft+80ft=160ft
90ft+160ft=250ft