If your question is will he have enough money, the answer is no he will not.
Answer:
yes
Step-by-step explanation:
Answer:
z = 3
Step-by-step explanation:
we use the method
(x^a)^b = x^(a*b)
so
(q^4)^z = q^(4*z)
now
4*z = 12
z = 12 / 4
so
z = 3
To begin lets say year one the population is 2,000
assume this in percent we can say that 2,000=100%
at the end of this year the population will have grown by 4% meaning that
100%+4% will be the new population =104%
but we know that 100%=2,000 so what about 104%=X?
so (104*2000)/100=2,080
So year 1 the population will have grown by 80 people amounting to 2080 people.
Now do it manually year by year until we reach the 15th year. i will help you up to year 3
2nd year= (2080*104)/100=2163.2
3rd year= (2163*104)/100=2249.728
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