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Nastasia [14]
3 years ago
10

Differences in linear and quadratic equations

Mathematics
1 answer:
BabaBlast [244]3 years ago
7 0

Answer:

linear equation has two variables doesn't involve any power

quadratic equation involves one of the variables raised to the second power.

Step-by-step explanation:

A <u>linear equation</u> in two variables doesn't involve any power higher than one for either variable. It has the general form Ax + By + C = 0, where A, B and C are constants. ... A <u>quadratic equation</u>, on the other hand, involves one of the variables raised to the second power.

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15 divided by 6 2/3 is 2.25. Or 2 1/4. Pick C
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he volume of a rectangular prism is cubic units, and the base area of the prism is square units. The height of the rectangular p
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Explanation: cubic units are used for volume, square units are used for he base, height, and area of a solid figure
4 0
3 years ago
8x+x^2-2y-64+y^2=0 standard form with explanation
xz_007 [3.2K]
X² + 8x +y² - 2y -64 =0
We see that the equation has x² and y² . Also we see that coefficients in front of x² and y² are equal. So this is an equation of the circle.
(x² + 8x) +(y² - 2y) -64 =0
(x² + 8x) +(y² - 2y) = 64
We need to complete square for x and y groups, that means it should be written in form (a+b)² or (a-b)².
Expressions in parenthesis we will write as a²+/-2ab+b², to write it after as (a+/-b)², because  a²+/-2ab+b² = (a+/-b)²

(x² + 2*4x) +(y² - 2*1y) = 64
(x² + 2*4x+4²) +(y² - 2*1y+1²) = 64+4²+1²
(x+4)² + (y-1)²= 81 Sometimes this is called a standard form of the circle.
(x+4)² + (y-1)²= 9² Sometimes it is required to write like this.

And if you are studying circles,ellipses  and hyperbolas, the standard form should look like
\frac{(x+4)^{2}}{9^{2}} + \frac{(y-1)^{2}}{9^{2}} =1






8 0
3 years ago
A parabola can be drawn given a focus of (6,-1) and a directrix of y = 9. What can be said about the parabola?​
zavuch27 [327]

Answer:

Since the focus is at (-6,-11) and the directrix is at y=9:

 

The vertex is halfway between the focus and the directrix, so the vertex is at (-6,-1).  (Draw this on graph paper if that doesn't make sense.)

 

The general form (conics form) of a parabola:  4p(y-k)=(x-h)^2 (vertex is (h,k) and "p" is the distance between the focus and vertex (or between vertex and directrix)).

 

(h,k) = (-6,-1)

 

p = 10 (distance between focus and vertex), so 4p = 40.

 

Therefore:

 

40(y+1)=(x+6)^2

 

Or if you need to rearrange to "vertex form":  y=(1/40)(x+6)^2 - 1

Step-by-step explanation:

3 0
3 years ago
What is the vertex of the absolute value function defined by f(x)=|x+5|+7?
irina1246 [14]

The vertex of the function f(x) = |x - a| is in (a, 0).

f(x) + a - shift the graph of function f(x) a units up.

Therefore:

The verex of y = |x + 5| is in (-5, 0).

The vertex of y + 7 = f(x) = |x + 5| + 7 is in (-5, 0 + 7) = (-5, 7).

6 0
4 years ago
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