Answer: no thank you
Step-by-step explanation:
For 5 free points
<h3>
Answer: (-infinity, 7]</h3>
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Explanation:
The first interval (-infinity, 3) describes any number less than 3, so we can write x < 3 in short hand (where x is the unknown number).
The second interval (-1, 7] means we start at -1 and stop at 7. We do not include -1 but include 7. So we say that 
(ie x is between -1 and 7; exclude -1, include 7)
If you were to graph each ona number line, you would see that the too intervals have overlapping parts. The right most edge extends out as far as x = 7. There is no left most edge as it goes onforever that direction.
Therefore, the to intervals combine to get 
which turns into the interval notation answer of (-infinity, 7]
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It might help to think of it like this: x < 3 and say "x is some number that is less than 3, or it is between -1 and 7". So x could be anything less than 7, including 7 itself.
Answers and Explanations:
4. They do not have a proportional relationship. For the first 3 sets, you can multiply x by 2.5 to get y. But that does not work for 8 and 18, so there is no proportional relationship between x and y.
5. Yes. For equilateral triangles, the side length is equal to the perimeter divided by 3, the number of sides. Vise versa, the side length times 3 equals the perimeter. If the side length is 3 in, multiply by 3 to get 9 in, the diameter.
6. Yes. it is proportional. X times 80 equals Y. In this case, in 8 hours, 640 tickets were sold.
<em>I hope these help! Feel free to give me Brainliest, if you thought the explanations helped your understanding. :)</em>
Range is the outputs possible
w(r(x))=(2-x^2)-2
w(r(x))=2-x^2-2
w(r(x))=-x^2
therefor the range is from 0 to -∞
Answer:
A graph that has an axis of symmetry at x = 3 would be x^2 -6x + 12
Step-by-step explanation:
In order to find a graph that has an axis of symmetry at 3, use the equation for the axis of symmetry of a quadratic.
x = -b/2a
In this equation, a is the coefficient of x^2 and b is the coefficient of x. So, if we use 3 as x and we choose a random number to be a (1), we can solve for the b.
3 = -b/2(1)
3 = -b/2
6 = -b
b = -6
Now that we have this, we can put those two numbers as coefficients. The constant at the end can be anything.
