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Yuliya22 [10]
3 years ago
9

How do you show your work for this problem?

Mathematics
2 answers:
laiz [17]3 years ago
7 0

Answer:

i cant see it

Step-by-step explanation:

zaharov [31]3 years ago
7 0
Make sure to put a picture next time, there’s no picture so I can’t help out.
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ʖ≖hi how are you and do u need help a homework?
Sergeeva-Olga [200]

Yes if you could help that would be so nice!!!!

8 0
3 years ago
Find the minimum or maximum value of the function g(x)=−3x2−6x+5
polet [3.4K]

Step-by-step explanation:

g(x) = ax²+bx+c

g(x)=−3x²−6x+5

a = -3, b= -6, c = 5

since a <0 , the function has only maximum value.

=> g'(x) = 0

-6x -6 = 0

-6x = 6

x = -1

the maximum value => g(-1) =

-3(-1)²-6(-1)+5 = -3+6+5 = 9

the domain : {x | x € Real numbers}

the range : {y| y ≤ 9, y € Real numbers}

the function is increasing for x < -1

the function is decreasing for x > -1

4 0
3 years ago
Write the following as a ratio: $72 for 488 photos
weeeeeb [17]

Answer:

The required ratio is 9 : 61

Step-by-step explanation:

Given,

$72 for 488 photos,

That is, the price of 488 photos = 72 dollars,

So, the ratio of price of photos and number of photos = \frac{72}{488}

∵ HCF(72, 488) = 8,

Thus, the ratio of price of photos and number of photos = \frac{72\div 8}{488\div 8}

= \frac{9}{61}

3 0
3 years ago
What is the ratio of 63 sit ups in 3 1/2 minutes
BlackZzzverrR [31]
The ratio would look like 63:3.5, if simplified it would look like 18:1
4 0
3 years ago
There are many ways to measure the reading ability of children. Research designed to improve reading performance is dependent on
ELEN [110]

Answer:

A 90% confidence interval to estimate the mean DRP score in Henrico County Schools  is =32±2.7280

i.e. C.I.  [29.3,34.7]

Hence the results are not significant.

Step-by-step explanation:

Given:

Total no of students =44

True mean =32

Standard deviation=11

And all 4 students score also given.

To Find:

90 % confidence interval and conclusion on it.

Solution:

Here for C.I. we required mean, standard deviation and no of students.

So mean =32,S.D.=11 and n=44

Therefore , For 90 % interval Zscore is Z=1.645

C.I.=mean±Z[Standard  deviation/Sqrt(n)]

=32±1.645[11/Sqrt(44)]

=32±1.645[1.6583]

=32±2.7280

i.e. C.I.  [29.3,34.7]

Now Here to commit on calculated interval we should check  value of Z-score

So we need to calculate the sample mean.

Sample mean =Sum of all values /Total no of values.

=[40+ 26 +39+ 14+ 42+ 18 +25+ 43+ 46 +27 +19+ 47+ 19 +26+ 35 +34+ 15+ 44 40+ 38+ 31+ 46 +52 +25+ 35 +35+ 33 +29 +34 +41 +49+ 28+ 42+ 47 +35 +48 +22 33+ 41 +51 +27 +14+ 54 +45]/44

=34.86

Z-score=(sample mean -true mean)/[standard deviation/Sqrt(n)]

=(34.86-32)/[11/Sqrt(44)]

Z=1.72465

For ,

P(Z≥1.72465)=0.08544

For 0.05 significance level  the results are not significant at  p<0.01.

Researcher claimed mean is not correct upto 0.05 significant level

i.e calculated mean and Sample mean are different.

Hence the results are not significant.

6 0
3 years ago
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