Answer:
The length of the rectangle (l) = 3 feet
The width of the rectangle (W) = 10 feet
Step-by-step explanation:
<u><em>Step(i):-</em></u>
<em>Given that the width of the rectangle = (x+1) feet</em>
<em>Given that the length of the rectangle = ( x-6) feet</em>
<em>The area of the rectangle = 30 square feet</em>
<u><em>Step(ii):-</em></u>
We know that the area of the rectangle
= length ×width
30 = ( x+1)(x-6)
30 = x² - 6x + x -6
⇒ x² - 5 x - 6 = 30
⇒ x² - 5 x - 6 - 30 =0
⇒ x² - 5 x - 36 =0
x² - 9 x +4x - 36 =0
x (x-9) +4 ( x-9) =0
( x+4 ) ( x-9) =0
( x+4 ) =0 and ( x-9) =0
x =-4 and x =9
<u><em>Step(iii):-</em></u>
we have to choose x =9
The length of the rectangle (l) = x-6 = 9-6 =3
The width of the rectangle (W) = x+1 = 9 +1 = 10
<u><em>Final answer:-</em></u>
The length of the rectangle (l) = 3 feet
The width of the rectangle (W) = 10 feet
I would say its A but I'm not 100%
Answer
22
Step-by-step explanation:
82-2=80-60=20+2=22
We know that 1 side is 100 and 1 angle is 90 degrees
we would need at least 1 more angle or 1 more side length to say that they are similar
no
but, if we asssume that DCB is a straignt line, then we can say that they are similar
2. if we say taht they are similar then DE=AB, so then 175=DE=AB
Answer:
7:56 A.M.
Step-by-step explanation:
1 hour and 59 mins = 119 mins
119+18 = 137
137/60 = 2 r 17
(10 - 2 = 8) - 17/60
Therefore they left at 7:56 A.M.