All categories

3 years ago

If a set of displacement vectors laid head to tail make a closed polygon, what is the resultant vector?

Physics

1 answer:

Papessa [141]3 years ago

4 0

The resultant vector is zero.

Explanation:

When you add displacement vectors using the head to tail method, you follow this procedure:

- Draw the first vector

- Draw the second vector, with its tail starting from the head of the first vector

- Draw the third vector, with its tail starting from the head of the second vector

.. and so on.

The resultant of the all vectors will be the vector connecting the tail of the 1st vector to the head of the last vector.

In this problem, the vectors make a closed polygon: this means that the head of the last vector coincides with the tail of the first vector.

Therefore, this means that the length of the resultant vector is zero.

Learn more about vector addition:

brainly.com/question/11220787

brainly.com/question/2892784

#LearnwithBrainly

You might be interested in

Please help, no links please! I dont understand stand this question and im going to cry

Vaselesa [24]

Answer:

I'm pretty sure its helium

3 0

3 years ago

Read 2 more answers

Help ASAP.

Temka [501]

Answer:

Depending on where people are located in the world (Northern hemisphere, Southern hemisphere, etc) depends on the difference in direction (North, South, east, West) which is most likely why it'd look different.

Explanation:

I dunno if this is along the lines of an answer you're looking for, but hope this helps :)

7 0

3 years ago

Two point charges are separated by 10 cm, with an attractive force between them of 15 N. Find the force between them when they a

suter [353]

Answer:

(a) the force is 8.876 N

(b) the magnitude of each charge is 4.085 μC

Explanation:

Part (a)

Given;

coulomb's constant, K = 8.99 x 10⁹ N.m²/C²

distance between two charges, r = 10 cm = 0.1 m

force between the two charges, F = 15 N

when the distance between the charges changes to 13 cm (0.13 m)

force between the two charges, F = ?

Apply Coulomb's law;

$F = \frac{Kq_1q_2}{r^2} \\\\let \ Kq_1q_2 = C\\\\F =\frac{C}{r^2} \\\\C = Fr^2\\\\F_1r_1^2 = F_2r_2^2\\\\F_2 =\frac{F_1r_1^2}{r_2^2} \\\\F_2 = \frac{15*0.1^2}{0.13^2} \\\\F_2 = 8.876 \ N$

Part (b)

the magnitude of each charge, if they have equal magnitude

$F = \frac{KQ^2}{r^2}$

where;

F is the force between the charges

K is Coulomb's constant

Q is the charge

r is the distance between the charges

$F = \frac{KQ^2}{r^2} \\\\Q = \sqrt{\frac{Fr^2}{K} } \\\\Q = \sqrt{\frac{15*(0.1)^2}{8.99*10^9} } = 4.085 *10^{-6} \ C\\\\Q = 4.085 \ \mu C$

4 0

3 years ago

Where is potential energy the greatest on a rollercoaster?

lidiya [134]

On a roller coaster, the greatest potential energy is at the highest point of the roller coaster

4 0

3 years ago

The first PCS technology used a form of time division multiplexing called ____. a. Time Division Multiple Access (TDMA) b. Gl

salantis [7]

Answer:

A. Time Division multiple Access (TDMA)

Explanation:

Time-division multiple access (TDMA) is a channel access method for shared-medium networks

It allows several users to share the same frequency channel by dividing the signal into different time slots. The users transmit in rapid succession, one after the other, each using its own time slot.

3 0

3 years ago