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Andreyy89
2 years ago
5

What is required for equilibrium to exist

Physics
1 answer:
creativ13 [48]2 years ago
8 0
They need to touch each other. Equilibrum, is when two things touch that arent the same heat, once they touch, they are equal in temperature, so they need to touch. hope i helped :D
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A skater extends her arms, holding a 2 kg mass in each hand. She is rotating about a vertical axis at a given rate. She brings h
Usimov [2.4K]

Explanation:

It is known that relation between torque and angular acceleration is as follows.

                    \tau = I \times \alpha

and,       I = \sum mr^{2}

So,      I_{1} = 2 kg \times (1 m)^{2} + 2 kg \times (1 m)^{2}

                       = 4 kg m^{2}

      \tau_{1} = 4 kg m^{2} \times \alpha_{1}

     \tau_{2} = I_{2} \alpha_{2}

So,      I_{2} = 2 kg \times (0.5 m)^{2} + 2 kg \times (0.5 m)^{2}

                     = 1 kg m^{2}

 as \tau_{2} = I_{2} \alpha_{2}

                   = 1 kg m^{2} \times \alpha_{2}        

Hence,     \tau_{1} = \tau_{2}

                  4 \alpha_{1} = \alpha_{2}

            \alpha_{1} = \frac{1}{4} \alpha_{2}

Thus, we can conclude that the new rotation is \frac{1}{4} times that of the first rotation rate.

8 0
3 years ago
Please help me! Science is not my best subject
Paul [167]
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4)Fluid
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8 0
3 years ago
A capacitor consists of two metal surfaces separated by an insulating layer. A new capacitor has no charge on either of its surf
mihalych1998 [28]
<h2>Answer:</h2><h3>(A) the positively charged surface increases and the energy stored in the capacitor increases.</h3>

When charging a capacitor transferring charge from one surface to the other, the first surface becomes negatively charged while the second surface becomes positively charged. As you transfer the charge, the voltage of the positively charged surface increases and the energy stored in the capacitor also increases. We can solve this by the definition of <em>capacitance</em><em> </em>that is <em>a  measure of the ability of a capacitor  to store energy. </em>For any capacitor, the capacitance is  a constant defined as:

C=\frac{Q}{V_{ab}}

To maintain C constant, if Q increases V also increases.

On the other hand, the potential energy U can be expressed as:

U=\frac{Q^{2}}{2C}

In conclusion, as Q increases the potential energy also increases.

5 0
3 years ago
First class second class or third class lever​​​​​​​​​
Black_prince [1.1K]

Answer:

the lever in which the fulcrum lies in middle is first

t

7 0
3 years ago
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A series RCL circuit is at resonance and contains a variable resistor that is set to 206Ω. The power dissipated in the circuit i
mash [69]

Answer:

Power dissipated in resistor 532 ohm is 0.503 watt

Explanation:

We have given in first case resistance R_1=206ohm

Power dissipated in this resistance is P_1=1.30watt

Power dissipated in the resistor is equal to P=\frac{v_{rms}}^2{R}

We have to find the power dissipated in the resistor is 1.30 watt

From the relation we can say that \frac{P_1}{P_2}=\frac{R_2}{R_1}

\frac{1.3}{P_2}=\frac{532}{206}

P_2=0.503watt

So power dissipated in resistor 532 ohm is 0.503 watt  

5 0
3 years ago
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