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mestny [16]
3 years ago
14

According to Newton’s first law of motion, if a person is swinging a rock st the end of a string and the string breaks, what wil

l the tendency of the rock be
Physics
1 answer:
balu736 [363]3 years ago
3 0

Travel in a straight path with constant velocity as the rock doesn't want to break its inertial frame.

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The chart shows data for an object moving at a constant acceleration. Which values best complete the chart? Time (s) Velocity (m
dangina [55]

Answer:

A.

x: 0

y: 0

z: 0

Explanation:

3 0
3 years ago
Read 2 more answers
The x component of vector is -27.3 m and the y component is +43.6 m. (a) What is the magnitude of ? (b) What is the angle betwee
lara [203]

Answer:51.44 units

Explanation:

Given

x component of vector is -27.3\hat{i}

y component of vector is 43.6\hat{j}

so position vector is

r=-27.3\hat{i}+43.6\hat{j}

Magnitude of vector is

|r|=\sqrt{27.3^2+43.6^2}

|r|=\sqrt{2646.25}

|r|=51.44 units

Direction

tan\theta =\frac{43.6}{-27.3}=-1.597

vector is in 2nd quadrant thus

180-\theta =57.94

\theta =122.06^{\circ}

4 0
3 years ago
Sound waves and some earthquake waves are what
Aleonysh [2.5K]

Answer:longitudinal waves

Explanation:

They are longitudinal waves

3 0
3 years ago
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Two identical loudspeakers, speaker 1 and speaker 2, are 2.0 m apart and are emitting 1700-hz sound waves into a room where the
Debora [2.8K]


Given the following in the problem:

Distances : 2.0 m and 4.0 m
Sound waves : 1700 hz
Speed of sound : 340 m/s

Get the wavelength of the sound by using the formula: 
Lambda = speed of sound/sound waves
Lambda = 340 m/s / 1700 hz
Lambda = 0.2 
Get the path length difference to the point from the two speakers 
L1 = 4mL2 = sqrt (42+ 22) m
Delta = 4.47

x = delta / lambda

If the outcome is nearly an integer, the waves strengthen at the point. If it is nearly an integer +0.5 the waves interfere destructively at the point. If it is neither the point is somewhat in in the middle.

Solving x = (4.47 – 4) / (0.2) = 2.35 an integer +0.5 so it’s a point of destructive interference. 
3 0
3 years ago
A tray of electronic components contains 15 components, 4 of which are defective. If 4 components are selected, what is the poss
dlinn [17]

Answer:

a) 0.0007326

b) 0.03223

c) 0.2418

d) 0.2418

Explanation:

To find different probabilities for the selection of components among eleven good and four defective components, we will use the Combination.

a) C(4,4) = 1; C(15,4) = 1365

P = \frac{C(4,4)}{C(15,4)} = \frac{1}{1365} = 0.0007326

b) C(4,3) = 4; C(11,1) = 11

P = \frac{C(4,3)*C(11,1)}{C(15,4)} = \frac{4*11}{1365} = 0.03223

c) C(4,2) = 6; C(11,2) = 55

P = \frac{C(4,2)*C(11,2)}{C(15,4)} = \frac{6*55}{1365} = 0.2418

d) C(11,4) = 330

P = \frac{C(11,4)}{C(15,4)} = \frac{330}{1365} = 0.2418

8 0
3 years ago
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