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Harlamova29_29 [7]
3 years ago
7

If the original quantity is 10 and the new quantity is 13 what is the percent increase

Mathematics
1 answer:
Harman [31]3 years ago
7 0

Answer:

As per the given statement:

Original quantity = 10

New quantity = 13

Change in quantity = New quantity - original quantity = 13-10 = 3

We have to find the percent increase.

\text{Percent increase} = \frac{\text{Change in quantity}}{\text{Original quanity}} \times 100

Substitute the given values we have;

\text{Percent increase} = \frac{3}{10} \times 100 = 30\%

Therefore, the percent increase is, 30%.

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What is the solution to the system of equations below? x 3 y = 15 and 4 x 2 y = 30 (6, 3) (3, 6) (7, –6) (–6, 7).
swat32

Answer: (6 , 3)

Step-by-step explanation: Given

x + 3y =15 ------- equation 1

4x + 2y = 30 --------- equation 2

x = 15 - 3y

Put value of x in equation 2

4 (15 - 3y) + 2y = 30

60 - 12y + 2y = 30

-10y = -30

divide by '-10' on both sides

y = 3

now, put value of y in equation 1

x + 3(3) = 15

x + 9 = 15

x = 15 - 9

x =  6

So , (x , y) = (6 , 3)

7 0
2 years ago
If n erasers have a weight of 80 grams, what is the total weight of 50 erasers?
Black_prince [1.1K]

Answer:

The\ weight\ of\ the\ 50\ erasers\ be\ \frac{4000}{n}\ grams.

Step-by-step explanation:

As given

if n erasers have a weight of 80 grams .

I.e

n erasera =  80 grams.

1 erasers weight .

1\ erasers\ weight = \frac{80}{n}

Now find out the weight of the 50 erasers.

Weight\ of\ 50\ erasers = \frac{50\times 80}{n}\ grams

Simplify the above

Weight\ of\ 50\ erasers = \frac{4000}{n}\ grams

Therefore\ the\ weight\ of\ the\ 50\ erasers\ be\ \frac{4000}{n}\ grams.

6 0
3 years ago
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Question 8. Quadrilateral ABCD is a rectangle. Find the value of x if the
babunello [35]

Answer:

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Step-by-step explanation:

6 0
2 years ago
Help i need to finish it today And can you explain the steps so i wont need help next time or if you don’t want to its okay :)
romanna [79]

Answer:

110 feet

Step-by-step explanation:

The formula to find the area of a rectangular prism is A = 2 (wl + hl + hw)

Substitute the values:

A = 2 (5x5 + 3x5 + 3x5)

A = 2 (25 + 15 + 15)

A = 2 (25 + 15 + 15)

A = 2 (55)

A = 110

6 0
3 years ago
Please help!! I’m not sure how to answer this question!!
nlexa [21]
<h3>Answer:  9V</h3>

=============================================================

Reason:

The volume expression of a cone with radius r and height h is

\frac{1}{3}\pi*r^2*h

Let's plug in the given height h = 12 and we'd get

\frac{1}{3}\pi*r^2*h\\\\\frac{1}{3}\pi*r^2*12\\\\\left(\frac{1}{3}*12\right)\pi*r^2\\\\4\pi*r^2\\\\

This is the volume of the first cone. We're told the first cone has a volume of V, so we can say V = 4\pi r^2

We can't find the actual numeric volume because we don't know what value replaces r. So we leave it as is.

The second cone has the same height (h = 12) but the radius is now 3 times in size. Instead of r, we use 3r

Replace every copy of r with 3r. Then simplify

4\pi*r^2\\\\4\pi*(3r)^2\\\\4\pi*9r^2\\\\9(4\pi r^2)\\\\9V\\\\

The radius tripled which results in a volume that's 9 times bigger.

3 0
1 year ago
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