Answer:
1. A. 12a^2 + 8a + 4
2. C. 4xy+16x-4y^2-16y
3. C. 64q^6r^8s^4
4. A. -4x^4y^6
Step-by-step explanation:
48a^3 + 32a^2 + 16a / 4a = (48a^3) / 4a + (32a^2) / 4a + (16a) / 4a = 12a^2 + 8a + 4.
So, the answer is A. 12a^2 + 8a + 4.
(2x-2y)(2y+8) = 4xy - 4y^2 + 16x - 16y.
So, the answer is C. 4xy+16x-4y^2-16y.
(-8q^3 * r^4 * s^2)^2 = (-8)^2 * q^6 * r^8 * s^4 = 64q^6r^8s^4.
So, the answer is C. 64q^6r^8s^4.
-12x^8y^8 / 3x^4y^2 = (-12 / 3) * (x^(8 - 4)) * (y^(8 - 2)) = -4x^4y^6.
So, the answer is A. -4x^4y^6.
Hope this helps!
Answer:
3937.5 or 3938 after round-off
Step-by-step explanation:
11 minutes 15 seconds = 11.25 minutes
5 members of the family shower 7 times a week for 11.25 minutes
=total of 393.75 minutes
393.75 times the amount of water used which is 10 litres becomes 3937.5
I hope this helps
Answer:The claim is correct
Explanation:Assume the given triangle ABCperimeter of triangle ABC = AB + BC + CA ............> I
Now, we have:D is the midpoint of AB, this means that:
AD = DB = (1/2) AB ..........> 1E is the midpoint of AC, this means that:
AE = EC = (1/2) AC ...........> 2DE is the midsegment in triangle ABC, this means that:
DE = (1/2) BC ...........> 3perimeter of triangle ADE = AD + DE + EA
Substitute in this equation with the corresponding lengths in 1,2 and 3:perimeter of triangle ADE = (1/2) AB + (1/2) BC = (1/2) AC
perimeter of triangle ADE = (1/2)(AB+BC+AC) .........> IIFrom I and II, we can prove that:perimeter of triangle ADE = (1/2) perimeter of triangle ABC
Which means that:perimeter of midsegment triangle is half the perimeter of the original triangle.
Hope this helps :)
We are given number of miles the 3 bike trips they took last month = 45.7, 40.9, and 38 miles.
Sam and Bruno were computing how many kilometers.
Also one kilometer equals 0.621 miles.
From this we can see than 1 kilometer is smaller unit and a mile is a larger unit.
In order to convert number of miles into kilometers, we need to divide each number of mile by 0.621 miles.
We always divide a larger value by a smaller value to get the smaller unit.
Therefore,
<h3>Bruno is correct. When going from a larger unit to a smaller unit you need to divide.</h3>