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3 years ago

How much space (volume) will 180.0 g of gold occupy?

Chemistry

1 answer:

Keith_Richards [23]3 years ago

6 0

Answer:

The space occupy by the 180.0 g of gold will be 9.32 cm³

Explanation:

Given data:

Mass of gold = 180.0 g

Volume occupy by the gold = ?

Solution:

The given problem will be solved through the density formula.

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

The density of gold from literature is 19.320 g/cm³

Now we will put the values in formula.

19.320 g/cm³ = 180.0 g/ V

V = 180.0 g/ 19.320 g/cm³

V = 9.32 cm³

The space occupy by the 180.0 g of gold will be 9.32 cm³.

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Complete Question

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