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MakcuM [25]
3 years ago
15

Which if the following matters occupies more space, assuming similar number of molecules? A.(Solid) B.(Liquid) C.(Gas) D. (Solid

and gas)​
Chemistry
2 answers:
dimaraw [331]3 years ago
6 0
Solid since it’s huge
Igoryamba3 years ago
5 0
The correct answer is (D) (solid and gas)
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The __ describes the steps you use during an experiment?
olasank [31]
I think the word your looking for is procedure 
3 0
3 years ago
Which of the following is a synthesis reaction?
Allushta [10]

Answer:  4 A1+3 02 → 2 Al2O3

Explanation: Two different atoms combines together to produce a compound.

7 0
2 years ago
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WHAT DOES THIS SAY AND WHAT THE ANSWER
notka56 [123]

It says

The majority of elements on the periodic table are ______________ (metals, nonmetals, or metalloids).  

The periodic table on the left separates elements into three groups: the metals (green in the table), nonmetals (orange), and metalloids (blue). Most elements are metals.

Apr 18, 2003

4 0
3 years ago
Calculate the molar mass of a compound if 0.372 mole of it has a mass of 152g​
Snowcat [4.5K]

Answer:

409 g/mol

Explanation:

you divide the mass by the moles to get the molar mass

5 0
3 years ago
A chemist titrates 160.0mL of a 0.3403M aniline C6H5NH2 solution with 0.0501M HNO3 solution at 25°C . Calculate the pH at equiva
maxonik [38]

Answer : The pH of the solution is, 5.24

Explanation :

First we have to calculate the volume of HNO_3

Formula used :

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the initial molarity and volume of C_6H_5NH_2.

M_2\text{ and }V_2 are the final molarity and volume of HNO_3.

We are given:

M_1=0.3403M\\V_1=160.0mL\\M_2=0.0501M\\V_2=?

Putting values in above equation, we get:

0.3403M\times 160.0mL=0.0501M\times V_2\\\\V_2=1086.79mL

Now we have to calculate the total volume of solution.

Total volume of solution = Volume of C_6H_5NH_2 +  Volume of HNO_3

Total volume of solution = 160.0 mL + 1086.79 mL

Total volume of solution = 1246.79 mL

Now we have to calculate the Concentration of salt.

\text{Concentration of salt}=\frac{0.3403M}{1246.79mL}\times 160.0mL=0.0437M

Now we have to calculate the pH of the solution.

At equivalence point,

pOH=\frac{1}{2}[pK_w+pK_b+\log C]

pOH=\frac{1}{2}[14+4.87+\log (0.0437)]

pOH=8.76

pH+pOH=14\\\\pH=14-pOH\\\\pH=14-8.76\\\\pH=5.24

Thus, the pH of the solution is, 5.24

4 0
4 years ago
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