The full decimal is 2.59328...
When you round up the answer is 2.6 atoms of Li
Answer:
The mole fraction of NaOH in an aqueous solution that contain 22.9% NaOH by mass=0.882
Explanation:
We are given that
Aqueous solution that contains 22.9% NaOH by mass means
22.9 g NaOH in 100 g solution.
Mass of NaOH(WB)=22.9 g
Mass of water =100-22.9=77.1
Na=23
O=16
H=1.01
Molar mass of NaOH(MB)=23+16+1.01=40.01
Number of moles =
Using the formula
Number of moles of NaOH

Molar mass of water=16+2(1.01)=18.02g
Number of moles of water

Now, mole fraction of NaOH
=

=0.882
Hence, the mole fraction of NaOH in an aqueous solution that contain 22.9% NaOH by mass=0.882
Answer:
u meant the answer to this ques
Explanation:
22
×12
------
44
22 ×
----------
264
-----------
or the answer can be 22×12=264
Answer- 33.4 kJ
Explanation-
100 g H2O x (1mol/18g) = 5.5 mol
q=(5.5 mol)(6.01 KJ/mol)= 33.4 kJ