Answer:
Explanation:
Mᵣ: 58.44 278.11
Pb(NO₃)₂ + 2NaCl ⟶ PbCl₂ + 2NaNO₃
m/g: 26.3
1. Moles of NaCl
(b) Moles of PbCl₂
(c) Theoretical yield of PbCl₂
(d) Percent yield
The spoon should be connected to the negative terminal of the battery. The other electrode should be made of silver.
Answer:
3.0 gram NaBr
Explanation:
A 5.0% aqueous solution of NaBr => 5 grams NaBr per 100 grams of solution
=> 0.05 gram NaBr per 1.0 gram of solution
=> grams of NaBr for 60g of 5% solution = 0.05·g·NaBr/g·Soln X 60g·Soln
= 3.0g NaBr