Resolver 3+(-2)-[6-(1+5)+4]

Mathematics

2 answers:

garri49 [273]3 years ago

6 0

Answer:-7

Step-by-step explanation:

To solve this 3+(-2)-[6-(1+5)+4]

We get

3-2-6-6+4

3+4-2-6-6

7-14

=-7

steposvetlana [31]3 years ago

5 0

Answer:

-3

Step-by-step explanation:

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3 years ago

Read 2 more answers

(10

Anni [7]

Given:

The matrix multiplication

$\begin{bmatrix}4&5&6\\1&2&3\end{bmatrix}\begin{bmatrix}10\\20\\30\end{bmatrix}$

To find:

The order of resulting matrix.

Solution:

We know that, if order of first matrix is $m_1\times n_1$ and the order of second matrix is $m_2\times n_2$ , then the order of these two matrices is $m_1\times n_2$ .

We have,

$\begin{bmatrix}4&5&6\\1&2&3\end{bmatrix}\begin{bmatrix}10\\20\\30\end{bmatrix}$

Here, the order of first matrix is $2\times 3$ and the order of the second matrix is $3\times 1$ . So, the order of the second matrix is $2\times 1$ . It is also written are 2 by 1.