The answer i think would be D
Let v = the launch velocity.
Because the launch angle is 40° (with the horizontal), the initial vertical velocity is
v* sin(40°) = 0.6428v m/s.
Assume g = 9.8 m/s² and ignore air resistance.
At maximum height, the vertical velocity is zero.
Because the maximum vertical height is 10 m, therefore
(0.6428v m/s)² - 2*(9.8 m/s²)(10 m) = 0
0.4132v² = 196
v = 21.78 m/s
Answer: 21.8 m/s (nearest tenth)
I want to help really bad but is there a photo of this ?
Answer:
velocity of rocket at the time of impact is 48.28 m/s
Explanation:
given,
rise of the rocket = 78 m
Velocity acquires by the rocket = 40 m/s
final velocity = 0 m/s
v = u + gt
0 = 40 - 9.81 × t
t = 4.08 s
now, calculation of displacement
= 40.8 m
total height = 40.8 + 78 = 118.8 m
velocity =
v = 48.28 m/s
velocity of rocket at the time of impact is 48.28 m/s
Answer:
False.
Explanation:
The forces acting on the rocket would be the engine pushing it forward, but it would also be the force of gravity and air friction acting in the reverse direction of the force of the engine. And so some energy in the form of heat, vibration, etc. would be lost to these forces, and the maximum amount of work would not be converted into kinetic energy.
So it's wrong with the statement. The work done by the engine-generated power would be higher than the Kinetic energy, as some of the energy is lost to non-conservative forces (gravity, air resistance, etc.).