Use the eq. of Young modulus Y=(F/A)/(∆l/lo)
dimana ∆l is the elongation of wire, lo is its initial length.
So ∆l = (F/A)lo/Y.
∆l = (1000N/(6.5 × 10^-7 m^2))×(2.5m)/(2.0 × 10^-11 N/m^2)
Use calculator to finish it.
Answer:
i hope this helps some
Explanation:
The time-averaged power of a sinusoidal wave is proportional to the square of the amplitude of the wave and the square of the angular frequency of the wave. This is true for most mechanical waves. If either the angular frequency or the amplitude of the wave were doubled, the power would increase by a factor of four.
The speed of a wave is dependant on four factors: wavelength, frequency, medium, and temperature. Wave speed is calculated by multiplying the wavelength times the frequency (speed = l * f).
Answer:
<h3>8. </h3>
m= 0. 113 kg
W = 1.1074 N
g = 9.8 m/ s²
<h3>9. </h3>
m= 870 kg
W = 8526 N
g = 9.8 m/s²
<h3>10.</h3>
a) weight on earth:
weight = mass × acceleration due to gravity (g)
<em>g</em><em> </em><em>on</em><em> </em><em>earth</em><em> </em><em>=</em><em> </em><em>9</em><em>.</em><em>8</em><em> </em><em>m</em><em>/</em><em>s</em><em>²</em>
W = 75 × 9.8
<u>W</u><u> </u><u>= </u><u>7</u><u>3</u><u>5</u><u> </u><u>N</u>
b) g on Mars
285 = 75 × g
g = 285/ 75
<u>g = 3.8 m/ s²</u>
Answer:
kE=0.0735 J
Explanation:
Given that
Radius ,R=10 cm = 0.1 m
Mass ,m= 3 kg
Angular speed ,ω = 3.5 rad/s
We know that moment of inertia for solid sphere given as
Kinetic energy
Now by putting the values
kE=0.0735 J
Therefore the kinetic energy will be 0.0735 J
Answer:
average shear strain in the rubber is 0.25rad
Explanation:
The base has a dimension of 20mm and 50mm.
frictional force is 50 N
using the expressed shear stress,
we will determine τ = 
τ = 50 / 1000
= 0.05MPa
shear stress τ = γ .G
τ = shear stress
γ = shear strain
G = 0.20MPa
γ = τ / G
= 0.05 / 0.20
= 0.25rad
average shear strain in the rubber is 0.25rad
