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Lady bird [3.3K]
3 years ago
9

An orbiting meteor has a mass of 5,123,788 g. What is the mass of the meteor in kg?

Physics
1 answer:
gavmur [86]3 years ago
6 0

Answer:

5123.79 kg

Explaination:

I did 5,123,788 divided by 1000 and got 5123.788

Then I rounded to the nearest 10th place.

Hope this helps, have a great day!

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4 years ago
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Acartravelingat15m/sstartstodeceleratesteadily.Itcomestoacompletestopin10seconds.Whatisit'sacceleration? a. 1500 m/s b. -1.5 m/s
Amiraneli [1.4K]

Answer:

b. -1.5 m/s²

Explanation:

Given the following data;

Initial velocity = 15m/s

Time = 10 seconds.

Since the car came to rest, final velocity = 0m/s

To find acceleration;

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of final speed from the initial speed all over time.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{initial \; speed  -  final \; speed}{time}

a = \frac{v  -  u}{t}

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a is acceleration measured in ms^{-2}

v and u is initial and final speed respectively, measured in ms^{-1}

t is time measured in seconds.

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6 0
3 years ago
A steel ball with mass m=5.21 g is moving horizontally with speed ????=412 m/s when it strikes a block of hardened steel with ma
docker41 [41]

Answer:

a) The speed of the block immediately after the collision is v_{2f}=(0.289\±0.002)m/s.

b) The impulse exerted on the block is p_{2}=(4.2772\±0.0296)kg*m/s.

Explanation:

Hi

a) As this is a perfectly elastic collision, we can use the formula  v_{2f}=(\frac{2m_{1} }{m_{1}+m_{2}} ) v_{1i}+ (\frac{m_{2}-m_{1}}{m_{1}+m_{2}} )v_{2i}, due v_{2i}=0m/s, we obtain v_{2f}=(\frac{2m_{1} }{m_{1}+m_{2}} ) v_{1i}. Then with the data that we know m_{1}=5.21g=0.00521kg, m_{2}=14.8kg and v_{1i}=412m/s, therefore v_{2f}=(\frac{2(0.00521kg) }{0.00521kg+14.8kg} ) 412m/s=0.289m/s or v_{2f}=(0.289\±0.002)m/s adding uncertainty.

b) Now that we know the speed we can use p_{2}=m_{2}*v_{f2} =14.8kg*(0.289\±0.002)m/s=(4.2772\±0.0296)kg*m/s.

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Answer:

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