The best activity for her to do to improve her range of motion is flexibility.
<h3>What are a few range of motion illustrations?</h3>
The term the range of motion (ROM) describes the extent to which a joint or muscle may be moved or stretched. Everybody has a distinct experience. For instance, whereas some people can perform a complete split, others cannot because their joints are stiff and their muscles are unable to extend as far.
<h3>What restricts motion range?</h3>
A joint is said to have a restricted range of motion when it cannot move easily and completely in its typical position. A mechanical issue within the joint, swollen tissues around the joint, or pain may restrict motion.
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<u>Voltage:</u>
It is basically the difference between the charges of the materials on the ends of the Wire
<em>also known as potential difference</em>
It is very similar to the movement of air, it moves from higher density to lower density. in this case, the change in density is the potential difference
So, since voltage is the difference between the charge available on the ends of a wire. Even if the wire splits in parallel circuit, the difference of the charges remains the same
<em>the more the potential difference, the faster electrons will move to the material with lower charge</em>
<u>Current:</u>
Current is the amount of electrons moving through a cross-section of a wire in a period of time
So basically, it is the amount of electrons that move across a given point on a wire in a period of time
If the wire splits, we will have the same amount of electrons moving through as they would if the wire was not split but now, the electrons passing are divided and hence, if we measure the current after the split, we will find that we have a lower current
that's because we have less charge moving through the cross-section of the wire since some of those electrons are moving through a different wire
That's why the current splits in a parallel circuit
A) 4.7 cm
The formula for the angular spread of the nth-maximum from the central bright fringe for a diffraction from two slits is

where
n is the order of the maximum
is the wavelength
is the distance between the slits
In this problem,
n = 5


So we find

And given the distance of the screen from the slits,

The distance of the 5th bright fringe from the central bright fringe will be given by

B) 8.1 cm
The formula to find the nth-minimum (dark fringe) in a diffraction pattern from double slit is a bit differente from the previous one:

To find the angle corresponding to the 8th dark fringe, we substitute n=8:

And the distance of the 8th dark fringe from the central bright fringe will be given by

Answer:
P = 2 pi R / v period of space station
F / m = v^2 / R centripetal force per unit of mass
So F / m = 4 pi^2 R^2 / (P^2 * R) = 4 pi^2 R / P^2
Also, F / m = 9.8 m/s^2 earth's gravitational attraction
So 9.8 = 4 pi^2 R / P^2 or R = 9.8 P^2 / 4 * pi^2) = 195 m
Or D = 2 R = 390 m the diameter required
Because of symmetry electric field component in the x axis cancels out. Now just use electric field formula and slap that sine of theta cause you want the vertical component of electric field and multiply that by two since there’s two charges. I’ve shown my work. Hope it helps✌