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Hunter-Best [27]
3 years ago
10

A student dance committee is to be formed consisting of 2 boys and 4 girls. If the membership is to be chosen from 5 boys and 6

girls, how many different committees are possible?
Mathematics
1 answer:
Paha777 [63]3 years ago
7 0

150 different committees are possible

<h3><u>Solution:</u></h3>

Given that a student dance committee is to be formed consisting of 2 boys and 4 girls

The membership is to be chosen from 5 boys and 6 girls

To find : number of different possible committees

A combination is a selection of all or part of a set of objects, without regard to the order in which objects are selected

<em><u>The formula for combination is given as:</u></em>

n C_{r}=\frac{n !}{(n-r) ! r !}

where "n" represents the total number of items, and "r" represents the number of items being chosen at a time

<em><u>We have to select 2 boys from 5 boys</u></em>

So here n = 5 and r = 2

\begin{aligned} 5 C_{2} &=\frac{5 !}{(5-2) ! 2 !}=\frac{5 !}{3 ! 2 !} \\\\ 5 C_{2} &=\frac{5 \times 4 \times 3 \times 2 \times 1}{3 \times 2 \times 1 \times 2 \times 1} \\\\ 5 C_{2} &=10 \end{aligned}

<em><u>We have to select 4 girls from 6 girls</u></em>

Here n = 6 and r = 4

\begin{aligned} 6 C_{4} &=\frac{6 !}{(6-4) ! 4 !}=\frac{6 !}{2 ! 4 !} \\\\ 6 C_{4} &=\frac{6 \times 5 \times 4 \times 3 \times 2 \times 1}{2 \times 1 \times 4 \times 3 \times 2 \times 1}=15 \end{aligned}

<em><u>Committee is to be formed consisting of 2 boys and 4 girls:</u></em>

So we have to multiply 5 C_{2} and 6 C_{4}

5 C_{2} \times 6 C_{4}=10 \times 15=150

So 150 different committees are possible

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