The balanced equation for the above reaction is as follows;
<span>Fe</span>₂<span>O</span>₃<span> + 3 CO --> 2 Fe + 3 CO</span>₂
<span>stoichiometry of CO to Fe is 3:2
molar volume states that 1 mol of any gas occupies a volume of 22.4 L
If 22.4 L contains 1 mol of CO
Then 3.65 L contains - 1/22.4 x 3.65 = 0.16 mol
3 mol of CO forms 2 mol of Fe
Then 0.16 mol of CO forms - 2/3 x 0.16 = 0.1067 mol of Fe
Therefore mass of Fe produced - 0.1067 mol x 55.8 g/mol = 5.95 g</span>
Answer:
334.08 g
Explanation:
87 proof = 43.5%
in 1L of liquid there is 43.5% alcohol/ethanol
1L (43.5/100) = 0.435 L alcohol
we want density in g/L because that's the volume u have
density 0.798 g/mL = 798 g/L
multiply the volume of alcohol by its density to get grams
0.435 L(798 g/L) = 334.08 g
Answer: Fluorine (see explanation)
Explanation:
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Answer: 7.07 grams
Explanation:
To calculate the moles :
According to stoichiometry :
1 mole of require 1 mole of
Thus 0.052 moles of will require= of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
As 1 mole of give = 1 mole of
Thus 0.052 moles of give = of
Mass of
Thus 7.07 g of will be produced from the given masses of both reactants.