All categories

3 years ago

Kinetic energy is _____.

Chemistry

2 answers:

NeTakaya3 years ago

6 0

The kinetic energy of<span> an object is the </span>energy<span> that it possesses due to its motion.</span>

ankoles [38]3 years ago

5 0

Explanation:

Kinetic energy is defined as the energy obtained by an object due to its motion.

This means that any object which is moving will have kinetic energy because it is in motion.

Mathematically, K.E = $\frac{1}{2}mv^{2}$

where, m = mass of object

v = volume of object

Whereas if an object is not moving and if it is only lying in a certain position then it will have only potential energy.

Thus, we can conclude kinetic energy is the energy obtained by an object due to its motion.

You might be interested in

1. During primary ecological succession, the initial formation of soil helps establish —

Art [367]

To think the answer is grasses

6 0

3 years ago

Formule of the acido perbromico

CaHeK987 [17]

The chemical formula for acido perbromico is HBrO4 or perbromic acid or bromate. It is an inorganic compound and an oxoacid of bromine. When an H+, the –ate ion is –ic acid: one less O is –ous acid, ttwo less is hypo- -ous acid and one more is per- -ic acid.

4 0

3 years ago

Cuál será el volumen de ácido clorhídrico concentrado, de densidad 1,19g/mL del 38% de ácido en peso, que se necesita para prepa

julsineya [31]

Answer:

Sorry I speak English can't help

7 0

3 years ago

Explain why elements with less protons require fewer neutrons to be stable compared to elements with more protons.

Solnce55 [7]

Answer:

The reason for this is because of the repulsive force between protons: The stronger the repulsion force, the more neutrons are needed to stabilize the nuclei.

Explanation:

7 0

3 years ago

16.25 g of water at 54 C relaeases 402.7 J. What will be its final temp?

leonid [27]

Data:
Q = 402.7 J → releases → Q = - 402.7 J
m = 16.25 g
T initial = 54 ºC
adopting: c = 4.184J/g/°C
ΔT (T final - T initial) = ?

Solving:

Q = m*c*ΔT
-402.7 = 16.25*4.184*ΔT
-402.7 = 67.99*ΔT
$\Delta\:T = \frac{-402.7}{67.99}$
$\boxed{\Delta\:T \approx -5.92\:^0C}$

If: ΔT (T final - T initial) = ?
$-5.92^0 = T_{final} - 54^0$
$T_{final} = 54^0 - 5.92^0$
$\boxed{\boxed{T_{final} = 48.08\:^0C}}\end{array}}\qquad\quad\checkmark$

8 0

4 years ago