All categories

2 years ago

Which of the following substances is non-living and is the smallest part of all matter?

Chemistry

2 answers:

dimaraw [331]2 years ago

3 0

A atoms. Atoms are the smallest part of any known matter

svetlana [45]2 years ago

3 0

Answer:

atoms

Explanation:

atoms are smallest part of element that cannot be broken down by any means

You might be interested in

Balance the chemical equation below using the smallest possible whole number stoichiometric coefficients NH3(g) + O2(g) + CH4(g)

alexira [117]

Answer:

$2NH_{3 (g)} + 3O_{2 (g)} +2CH_{4 (g)} --> 2HCN_{(aq)} + 6H_{2}O_{(l)}$

Explanation:

5 0

3 years ago

Which method would you use to separate silt from water

jonny [76]

The answer is "filtration"

Filtration is used to seprate a solid from a liquid in which it is suspended. Filtration is also used to separate a substance from a mixture because one is insoluble in the solvent and the other is solube. The separation is due to particle size.

I hope this helps.

8 0

2 years ago

Read 2 more answers

What's the atomic weight of salt ?

marta [7]

Answer:

58.44 g/mol

Explanation:

58.44 g/mol

4 0

2 years ago

Read 2 more answers

A pure compound is found to be 40.0% carbon by mass, 6.73% hydrogen by mass, and 53.3% oxygen by mass. determine the empirical f

ratelena [41]

Since there is no weight, I would assume that this is a 100g of pure compound.
Okay so I would be changing the percentage to gram to solve for the mole.
So
40.0g C (1 mol C/12.01 g C) = 3.33 mol C
6.73g H (1 mol H/1.01 g H ) = 6.66 mol H
53.3g O (1 mol O/16.00 g O) = 3.33 mol O

With that, two of our moles is 3.33, so we consider that are our 1, as it is also the lowest. Therefore the empirical formula is CH2O

3 0

2 years ago

The formation constant for the reaction ag (aq) 2nh3(aq) ag(nh3)2 (aq) is kf = 1.7 × 107 at 25°c. what is δg° at this temperatur

anzhelika [568]

The value of ΔG° at this temperature is -18034.18 J/mol

Calculation,

Given information

formation constant (Kf)= 1.7 × $10^{7}$

Universal gas constant (R) = 8.314 J/K• mol

Temperature = 25° C = 25 °C + 273 = 300 K

Formula used:

ΔG° = -RT㏑Kf

By putting the valur of R,T, Kf we get the value of ΔG°

ΔG° = - 8.314 J/K• mol×300K㏑ 1.7 × $10^{7}$

ΔG° = -2494.2㏑ 1.7 × $10^{7}$ = -18034.18 J/mol

So, change in standard Gibbs's free energy is -18034.18 J/mol

Learn about formation constant

brainly.com/question/14011682

#SPJ4

8 0

1 year ago