Answer:
sp2
Explanation:
Orbital hybridization is defined as the changes in the orbitals of atoms when they pair with electrons of other atoms to form chemical bonds.
C atoms in C2Cl4 or tetrachloroethene have a total of three bond pairs, two with each chlorine atom and one with other carbon atom and zero lone pairs. Thus, C atoms in C2Cl4 is sp2 hybridized.
Hence, the correct answer is "sp2".
Answer: All organic compound depends on H-bonding with water. more stronger H-bonding with water more will be soluble.
Explanation:
1. It depends primarily upon the function groups of that compound. It also depends on the size of the compound.
2. some organic compound which soluble in water for example: alcohols, ethers, carboxylic acids. Because of the functional groups attached to the organic structure (the C-H backbone) are what effect the solubilities.Like carboxylic acids and alcohols form hydrogen bonds with the water, helping to solubilize it.
3. Take alcohols for example: methanol, ethanol, and isopropanol are all completely soluble in water. By the time you get to butanol and some of the larger alcohols, including those with more complex structures, they tend to be less soluble.
N₂ + 3H₂ → 2NH₃
Based on the reaction, Mole ratio of H₂ to N₂ is 3 : 1 [ 1N₂ + 3H₂ → 2NH₃]
∴ if moles of Hydrogen = 6.34 mol
then moles of nitogen = 6.34 mol ÷ 3
= 2.11 moles
∴ 2.11 moles (OPTION 2) of Nitrogen is needed to convert 6.34 moles of Hydrogen into ammonia.