3(x - 2) < 18 and h + 6 > -3h + 12 would be graphed with an open circle.
Open circle is a term used for numbers that are less than (<) or greater than (>). On the other hand, Closed circle is used for numbers that are less than or equal to (≤ ) and greater than or equal to (≥).
Here, we are given four inequalities, let us check them one by one-
A. h + 6 > -3h + 12
⇒ 4h > 6
or h > 3/2
Here, we see that there is no equality sign, this means that 3/2 won't be included and hence h + 6 > -3h + 12 would be an open circle inequality.
B. 7 ≥ d/3
⇒ d ≤ 21
Here, we can clearly see the equality sign which means that 21 will be included. Hence, 7 ≥ d/3 would not be graphed with an open circle.
C. 3(x - 2) < 18
x - 2 < 6
x < 8
Here, we see that there is no equality sign, this means that 8 won't be included and hence 3(x - 2) < 18 would be graphed with an open circle.
D. 2y ≤ 14
y ≤ 7
Here, we can clearly see the equality sign which means that 7 will be included. Hence, 2y ≤ 14 would not be graphed with an open circle.
Thus, 3(x - 2) < 18 and h + 6 > -3h + 12 would be graphed with an open circle.
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Answer:
(H)
Step-by-step explanation:
because it is the closest to a right angle (45 degree angle) and 45 is only off by 3 from 48. hope this help :)
The answer is c. they are indeed vertical angles
Answer:
Attached is the image of the solution . cheers
Two in five chance of drawing a shape with all sides congruent
