You can get a vertical asymptote at x=1 using y = 1/(x-1)
You can generate a hole at x=3 by multiplying by (x - 3/(x - 3) which is undefined at x=3 but otherwise equals 1
You can move the horizontal asymptote up to y=2 by adding 2
y = (x - 3)/((x - 1)(x - 3)) + 2
Answer:
Option A.
Step-by-step explanation:
We need to find a table for which the y-value will be the greatest for very large values of x.
From the given table it is clear that the largest value of x in all tables is 5.
In table A, y=64 at x=5.
In table B, y=32 at x=5.
In table C, y=40 at x=5.
In table D, y=13 at x=5.
It is clear that 64 is the greatest value among 64, 32, 40 and 13.
It means table in option A represents the function for which the y-value will be the greatest for very large values of x.
Therefore, the correct option is A.
Answer:
254.57 in^3
Step-by-step explanation:
A cylinder has a height of 9 inches. The radius of the cylinder is 1 / 3 the height of the cylinder. What is the approximate volume of the cylinder?
volume of a cylinder = nr^2h
n = 22/7
r = radius
radius = 9 x 1/3 = 3 inches
(22/7) x (3^2) x 9 = 254.57 in^3
