Which of the following describes the stage that occurs after evaporation in the water cycle?

an empty relative density bottle weights 20g. the bottle weights 40g when filled with petrol and 60g when filled with water. det

Kobotan [32]

Answer:

500 Kg/m³

Explanation:

From the question given above, the following data were obtained:

Mass of empty bottle = 20 g

Mass of bottle + petrol = 40 g

Mass of bottle + water = 60 g

Density of water = 1000 Kg/m³

Density of petrol =?

Next, we shall determine the mass of water. This can be obtained as follow:

Mass of empty bottle = 20 g

Mass of bottle + water = 60 g

Mass of water =?

Mass of water = (Mass of bottle + water) – (Mass of empty bottle)

Mass of water = 60 – 20

Mass of water = 40 g

Converting 40 g to Kg, we have:

1000 g = 1 Kg

Therefore,

40 g = 40 × 1 Kg / 1000 g

40 g = 0.04 Kg

Next, we shall determine the volume of the bottle by calculating the volume of water. This can be obtained as follow:

Mass of water = 0.04 Kg

Density of water = 1000 Kg/m³

Volume of water =?

Density = mass / volume

1000 = 0.04 / volume

Cross multiply

1000 × volume = 0.04

Divide both side by 1000

Volume of water = 0.04 / 1000

Volume of water = 4×10¯⁵ m³

Thus, the volume of the bottle is 4×10¯⁵ m³

Next, we shall determine the mass of the petrol. This can be obtained as follow:

Mass of empty bottle = 20 g

Mass of bottle + petrol = 40 g

Mass of petrol =?

Mass of petrol = (Mass of bottle + petrol ) – (Mass of empty bottle)

Mass of petrol = 40 – 20

Mass of petrol = 20 g

Converting 20 g to Kg, we have:

1000 g = 1 Kg

Therefore,

20 g = 20 × 1 Kg / 1000 g

20 g = 0.02 Kg

Finally, we shall determine the density of the petrol. This can be obtained as follow:

Mass of petrol = 0.02 Kg

Volume of petrol = 4×10¯⁵ m³

Density of petrol =?

Density = mass / volume

Density of petrol = 0.02 / 4×10¯⁵

Density of petrol = 500 Kg/m³

4 0

3 years ago

Part A Find ΔS∘ for the reaction between nitrogen gas and hydrogen gas to form ammonia: 12N2(g)+32H2(g)→NH3(g) Express your answ

inessss [21]

Answer:

$\Delta S^{0}$ for the given reaction is -99.4 J/K

Explanation:

Balanced reaction: $\frac{1}{2}N_{2}(g)+\frac{3}{2}H_{2}(g)\rightarrow NH_{3}(g)$

$\Delta S^{0}=[1mol\times S^{0}(NH_{3})_{g}]-[\frac{1}{2}mol\times S^{0}(N_{2})_{g}]-[\frac{3}{2}mol\times S^{0}(H_{2})_{g}]$

where $S^{0}$ represents standard entropy.

Plug in all the standard entropy values from available literature in the above equation:

$\Delta S^{0}=[1mol\times 192.45\frac{J}{mol.K}]-[\frac{1}{2}mol\times 191.61\frac{J}{mol.K}]-[\frac{3}{2}mol\times 130.684\frac{J}{mol.K}]=-99.4J/K$

So, $\Delta S^{0}$ for the given reaction is -99.4 J/K

7 0

4 years ago

In a lab in New York, Thomas and Nikola collected data over several trials. Thomas recorded his measurements as 10.0 A, 11 A, an

Anna11 [10]

Nikola's reading has a lower range and it is logical to conclude that his reading is more precise.

Explanation:

Precision is the ability to reproduce the same set of result from a measurement. The more repeatability a measurement is, the more precise it is.

From the given pool of data, it is easy to determine which set of data is more precise over the other.

Thomas measurements: 10.0 A, 11 A, and 8 A

Nikola measurements: 9.0 A, 9.2 A, 8.8 A

Using the range method, it is possible to find the precision in this pool of data.

Method and Solution:

Find the range of the sample:

Range = highest value - lowest value

Thomas measurement; Range = (11-8)A = 3.0A

Nikola measurement; Range = (9.2-8.8)A = 0.4A

Find the mean of the samples:

Mean of Thomas measurement = $\frac{10 + 11+ 8}{3}$ = $\frac{29}{3}$ = 9.7A

Mean of Nikola measurement = $\frac{9+ 9.2+ 8.8}{3}$ = $\frac{27}{3}$ = 9A

Now let us quote the range of value of the mean of each measurement:

Thomas 9.7±3.0A

Nikola 9.0± 0.4A

Nikola's reading has a lower range and it is logical to conclude that his reading is more precise.

Learn more:

mean calculation brainly.com/question/12068498

#learnwithBrainly

5 0

3 years ago

Which process causes earth surface to warm

Sedbober [7]

Air production process

6 0

3 years ago

Read 2 more answers

Calculate the enthalpies of formation, ΔHf∘, of the group 1 fluoride compounds from their elements using the Born–Haber cycle.

maxonik [38]

Answer:

Enthalpy of formation of KF = -555 kJ/mol

Enthalpy of formation of CsF = -539kJ/mol

Explanation:

Explanations are provided in the attachment below

5 0

4 years ago