Answer: I think that you have to find it in your lesson
Explanation:
Answer:
of is 0.0513
Solubility equilibrium of :
Solubility product of () is written as-
Where and represents equilibrium concentration (in molarity) of and respectively.
Molar mass of = 183.48 g/mol
So, solubility of = = 0.234M
1 mol of gives 1 mol of and 2 moles of upon dissociation.
so, = 0.234 M and =
so,