A student wants to know how far above the ground the top of a leaning flagpole is. At high noon, when the sun is almost directl
1 answer:
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Answer:
X, process, y
-2, 3(-2), -6
-1, 3(-1), -3
0, 3(0), 0
1, 3(1), 3
2, 3(2), 6
X = -2, -1, 0, 1, 2,
Y = -6, -3, 0, -3, -6
Step-by-step explanation:
Coordinates for the graph: (-2,-6), (-1,-3), (0,0), (1,3), (2,6)
Graph is the image I added onto this.
Solving for Y below:
3(-2)= -6
3(-1)= -3
3(0)= 0
3(1)= 3
3(2)= 6
Hope this helps.
