Triple the sum of 45 and 55

Let g(x)=x-3 and h(x)=x^2+6 find (h o g) (1)

cupoosta [38]

$g(x)=x-3 \ \ \ and\ \ \ h(x)=x^2+6 \\\\(h \circ g) (1)=h\bigg (g(1)\bigg)=h\bigg(1-3\bigg)=h(-2)=(-2)^2+6=4+6=10$

5 0

3 years ago

A recipe calls for 1/3 cup of grated Parmesan cheese for 8 servings of spaghetti sauce. How many servings can be made with 2 cup

Darya [45]

You can make 48 servings with 2 cups of Parmesan cheese

4 0

3 years ago

Write the names of 5 object which are longer than your hand- span in your surrounding

Semenov [28]

5 object which are longer than your hand- span in my surrounding is Note book, Laptop, Window, Curtain, Table.

Hand span is a measure of distance from the tip of the thumb to the tip of the little finger with the hand fully extended.

Hand span is a measure that has been used for many years. By placing the hand on the edge of a piece of paper and marking the tips of the thumb and little finger, the student can measure a straight line. This is a better method than placing the hand directly on the ruler.

Hand span and cubit are not used as standard units of length because their sizes vary from person to person. So, two different persons may give different measurements for the same length, which is not desirable for a standard unit.

Measure using yours hands and write as per your hand-span measurement.

Therefore,

5 object which are longer than your hand- span in my surrounding is Note book, Laptop, Window, Curtain, Table.

Find out more information about hand span here

brainly.com/question/993795

#SPJ4

4 0

2 years ago

Four internet providers offer similar services to almost everyone in the city. Any new company would have to engage in a price w

aniked [119]

What are you asking? If it’s true or false it’s TRUE?

6 0

3 years ago

While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem

Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = population proportion.

So, Null Hypothesis, $H_0$ : p = 0.013 {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, $H_A$ : p > 0.013 {means that this is an unusually high number of faulty modems}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion faulty modems= $\frac{10}{367}$ = 0.027

n = sample of modems = 367

So, the test statistics = $\frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }$

= 2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0

3 years ago