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Lilit [14]
3 years ago
11

In an arithmetic​ sequence, the nth term an is given by the formula An=a1+(n−1)d​, where a1

Mathematics
1 answer:
Gnesinka [82]3 years ago
5 0

Answer:

88

Step-by-step explanation:

We are given that in arithmetic sequence , the nth term a_n is given by the formula

A_n=a_1+(n-1)d

Where a_1=first term

d=Common difference

In an geometric sequence, the nth term is given by

a_n=a_1r^{n-1}

Where r= Common ratio

1,4,7,10,..

We have to find 30th term.

a_1=1,a_2=4,a_3=7,a_4=10

d=a_2-a_1=4-1=3

d=a_3-a_2=7-4=3

d=a_4-a_3=10-7=3

r_1=\frac{a_2}{a_1}=\frac{4}{1}=4

r_2=\frac{a_3}{a_2}=\frac{7}{4}

r_1\neq r_2

Therefore, given sequence is an arithmetic sequence because the difference between consecutive terms is constant.

Substitute n=30 , d=3 a=1 in the given formula of arithmetic sequence

Then, we get

a_{30}=1+(30-1)(3)=1+29(3)=1+87=88

Hence, the 30th term of sequence is 88.

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<img src="https://tex.z-dn.net/?f=cos%20%5B%20arctan%28%5Cfrac%7B12%7D%7B5%7D%29%20-%20arcsin%20%28%5Cfrac%7B-3%7D%7B5%7D%29%5D"
qwelly [4]

Answer: -16/65

Step-by-step explanation:

Drawing the right triangle (as attached) gives us that \arctan \left(\frac{12}{5} \right)=\arcsin \left(\frac{12}{13} \right)

Also, -\arcsin \left(-\frac{3}{5} \right)=\arcsin \left(\frac{3}{5} \right)

This means our original expression is equal to:

\cos \left[\arcsin \left(\frac{12}{13} \right)+\arcsin \left(\frac{3}{5} \right) \right]

Using the cosine addition formula, which states \cos(a+b)=\cos a \cos b-\sin a \sin b, we get this itself is equal to:

\cos \left(\arcsin \left(\frac{12}{13} \right) \right)\cos \left(\arcsin \left(\frac{3}{5} \right)\right)-\sin \left(\arcsin \left(\frac{12}{13} \right) \right)\sin \left(\arcsin \left(\frac{3}{5} \right)\right)

Since \sin^{2} \theta+\cos^{2} \theta=1, we know that:

\sin^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)+\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=1\\\\\frac{144}{169} +\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=1\\\\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=\frac{25}{169}\\\\cos \left(\arcsin \left(\frac{12}{13} \right)\right)=\frac{5}{13}

Similarly, cos(arcsin(3/5))=4/5.

This means the given expression is equal to:

\left(\frac{5}{13} \right) \left(\frac{4}{5} \right)-\left(\frac{12}{13} \right) \left(\frac{3}{5} \right)\\\\\frac{20}{65}-\frac{36}{65}=\boxed{-\frac{16}{65}}

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WHAT is the scale factor of the dilation?<br> PLEASE HELPPp c:
Artist 52 [7]

Answer:

2.5

Step-by-step explanation:

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2 * x = 5

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3 years ago
Help!! BRAINLIEST TOO!
natulia [17]

Answer:

36.5 inches

Step-by-step explanation:

Given

See attachment for the given data

Required

Which length is closest to 4.2lb

The given data is a linear dataset.

So, we start by calculating the slope (m)

m =\frac{y_2 - y_1}{x_2 - x_1}

Pick any two corresponding points from the table

So, we have:

(x_1,y_1) = (8,1.21)

(x_2,y_2) = (12,1.63)

So:

m =\frac{y_2 - y_1}{x_2 - x_1}

m =\frac{1.63 - 1.21}{12 - 8}

m =\frac{0.42}{4}

m =0.105

The linear equation is then calculated using:

y = m(x - x_1) + y_1

This gives:

y = 0.105 * (x - 8) + 1.21

Open bracket

y = 0.105x - 0.84 + 1.21

y = 0.105x + 0.37

To get the length closest to 4.2lb,

we set y = 4.2

Then solve for x

So, we have:

y = 0.105x + 0.37

4.2 = 0.105x + 0.37

Collect like terms

0.105x= 4.2 - 0.37

0.105x= 3.83

Solve for x

x= 3.83/0.105

x\approx 36.5

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