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2 years ago

The owners of the pet sitting business have set aside $48 to purchase chewy toys for dogs, 2,

Mathematics

1 answer:

Contact [7]2 years ago

7 0

6 chewy toys and 6 cat collars are needed to have the same amount or price at both stores.

<h3>Equation</h3>

An equation is an expression used to show the relationship between two or more angles and variables.

Let x represent the number of dogs and y represent the number of cats collars. Hence:

At Marco's market:

2x + 6y = 48 (1)

At Sonia's superstore:

4x + 4y = 48 (2)

Graphing both equations, the solution is at (6,6)

6 chewy toys and 6 cat collars are needed to have the same amount or price at both stores.

Find out more on Equation at: brainly.com/question/13763238

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PLEASE HELP ME GUYS OR I WONT PASS this calculus!!!!

KonstantinChe [14]

Answer:

b. $\displaystyle \frac{1}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

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Function Notation
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Rule [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle H(x) = \sqrt[3]{F(x)}$

Step 2: Differentiate

Rewrite function [Exponential Rule - Root Rewrite]: $\displaystyle H(x) = [F(x)]^\bigg{\frac{1}{3}}$
Chain Rule: $\displaystyle H'(x) = \frac{d}{dx} \bigg[ [F(x)]^\bigg{\frac{1}{3}} \bigg] \cdot \frac{d}{dx}[F(x)]$
Basic Power Rule: $\displaystyle H'(x) = \frac{1}{3}[F(x)]^\bigg{\frac{1}{3} - 1} \cdot F'(x)$
Simplify: $\displaystyle H'(x) = \frac{F'(x)}{3}[F(x)]^\bigg{\frac{-2}{3}}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle H'(x) = \frac{F'(x)}{3[F(x)]^\bigg{\frac{2}{3}}}$

Step 3: Evaluate

Substitute in x [Derivative]: $\displaystyle H'(5) = \frac{F'(5)}{3[F(5)]^\bigg{\frac{2}{3}}}$
Substitute in function values: $\displaystyle H'(5) = \frac{6}{3(8)^\bigg{\frac{2}{3}}}$
Exponents: $\displaystyle H'(5) = \frac{6}{3(4)}$
Multiply: $\displaystyle H'(5) = \frac{6}{12}$
Simplify: $\displaystyle H'(5) = \frac{1}{2}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

5 0

3 years ago

3/4 Tones = __ lb???? HELP ASAP Thank you

Shtirlitz [24]

The answer is 1500 pound because 1 ton = 2,000 pounds. 1/4 of a ton = 500 pounds. So 3/4 tons = 500*3 =1500 pounds.

6 0

3 years ago

Read 2 more answers

The zeros of the function f(x)=(x+2)^2 - 25 are?

zloy xaker [14]

Zeros of the function
f(x) = (x + 2)² - 25
f(x) = (x + 2)(x + 2) - 25
f(x) = x(x + 2) + 2(x + 2) - 25
f(x) = x(x) + x(2) + 2(x) + 2(2) - 25
f(x) = x² + 2x + 2x + 4 - 25
f(x) = x² + 4x + 4 - 25
f(x) = x² + 4x - 21
x² + 4x - 21 = 0
x = -(4) +/- √((4)² - 4(1)(-21))
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x = -4 +/- √(16 + 84)
 2
x = -4 +/- √(100)
 2
x = -4 +/- 10
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x = -2 + 5
x = -2 + 5 x = -2 - 5
x = 3 x = -7
f(x) = x² + 4x - 21
f(3) = (3)² + 4(3) - 21
f(3) = 9 + 12 - 21
f(3) = 21 - 21
f(3) = 0
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or
f(x) = x² + 4x - 21
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f(-7) = 21 - 21
f(-7) = 0
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Vertex
X - Intercept
-b/2a = -(4)/2(1) = -4/2 = -2

Y - Intercept
y = x² + 4x - 21
y = (-2)² + 4(-2) - 21
y = 4 - 8 - 21
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3 years ago

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maria [59]

(-4) is the same as x, so looking the conditions that are the results for the function, you realize:

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x < -3 ; x = -4 ; -4 < -3 (it's true), in other words, -4 is less than -3, so f(-4) = -2

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3 years ago

Answer as a fraction. do not include space in your answer. 4 2/3 + 7/9

kvv77 [185]

Answer:

Step-by-step explanation:

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2 years ago