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3 years ago

Which choice is the appropriate simplified form and restriction for the variable? 3x^2+9x over x^2-2x-15

2 answers:

7 0

(3x^2 + 9x) / ( x^2 -2x -15)

Factor both polynomials

(3x)(x+3) / (x-5)(x+3) = 3x/(x+5)

The simplified form is 3x/(x+5)

The restriction for the variable is x ≠ -3 (this is because you can only simplify the factor x-3 if its value is not zero).

crimeas [40]3 years ago

3 0

If you would like to know what is the appropriate simplified form and restriction for the variable, you can calculate this using the following steps:

(3x^2 + 9x) / ( x^2 - 2x - 15) = (3x * (x + 3)) / ((x - 5) * (x + 3)) = 3x / (x - 5)

The simplified form is 3x / (x - 5) and the restriction for the variable would be x <span>≠</span> 5 and x ≠ -3.

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PLS HELP ME ASAP FOR 12 and 13!!! (SHOW WORK FOR BOTH!!!) + LOTS KF POINTS!!

pychu [463]

12.
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2x - 5 - 9y + 8 + 16y
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3 years ago

Which of these statements is true for f(x)=(1/10)^x

lana66690 [7]

Step-by-step explanation:

Considering the function

$f\left(x\right)=\:\left(\frac{1}{10}\right)^x$

Analyzing option A)

Considering the function

$f\left(x\right)=\:\left(\frac{1}{10}\right)^x$

Putting $x = 1$ in the function

$f\left(1\right)=\:\left(\frac{1}{10}\right)^1$

$f\left(1\right)=\:\left\frac{1}{10}\right$

So, it is TRUE that when $x = 1$ then the out put will be $f\left(1\right)=\:\left\frac{1}{10}\right$

Therefore, the statement that '' The graph contains $\left(1,\:\frac{1}{10}\right)$ '' is TRUE.

Analyzing option B)

Considering the function

$f\left(x\right)=\:\left(\frac{1}{10}\right)^x$

The range of the function is the set of values of the dependent variable for which a function is defined.

$\mathrm{The\:range\:of\:an\:exponential\:function\:of\:the\:form}\:c\cdot \:n^{ax+b}+k\:\mathrm{is}\:\:f\left(x\right)>k$

$k=0$

$f\left(x\right)>0$

Thus,

$\mathrm{Range\:of\:}\left(\frac{1}{10}\right)^x:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)>0\:\\ \:\mathrm{Interval\:Notation:}&\:\left(0,\:\infty \:\right)\end{bmatrix}$

Therefore, the statement that ''The range of $f(x)$ is $y > \frac{1}{10}$ " is FALSE

Analyzing option C)

Considering the function

$f\left(x\right)=\:\left(\frac{1}{10}\right)^x$

The domain of the function is the set of input values which the function is real and defined.

As the function has no undefined points nor domain constraints.

So, the domain is $-\infty \:$

Thus,

$\mathrm{Domain\:of\:}\:\left(\frac{1}{10}\right)^x\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

Therefore, the statement that ''The domain of $f(x)$ is $x>0$ '' is FALSE.

Analyzing option D)

Considering the function

$f\left(x\right)=\:\left(\frac{1}{10}\right)^x$

As the base of the exponential function is less then 1.

i.e. 0 < b < 1

Thus, the function is decreasing

Also check the graph of the function below, which shows that the function is decreasing.

Therefore, the statement '' It is always increasing '' is FALSE.

Keywords: function, exponential function, increasing function, decreasing function, domain, range

Learn more about exponential function from brainly.com/question/13657083

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Answer:

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3 years ago