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hoa [83]
3 years ago
10

A solid with volume 8 cubic units is dilated by a scale factor of k to obtain a solid with volume V cubic units. Find the value

of k which results in an image with each given volume.
a. 216 cubic units

k=

b. 1 cubic unit

k=

c. 1,000 cubic units

k=
Mathematics
1 answer:
Katena32 [7]3 years ago
8 0

Answer:

a. k = 27

b. k = 216

c. k = 0.216

Step-by-step explanation:

The value of the scale factor can be given by the following formula:

k = \frac{Final\ Volume}{Initial\ Volume}

where,

Initial Volume = 8 cubic units

a.

Final Volume = 216 cubic units

Therefore,

k = \frac{216\ cubic\ units}{8\ cubic\ units}

<u>k = 27</u>

<u></u>

b.

Final Volume = 1 cubic units

Therefore,

k = \frac{216\ cubic\ units}{1\ cubic\ units}

<u>k = 216</u>

<u></u>

c.

Final Volume = 1000 cubic units

Therefore,

k = \frac{216\ cubic\ units}{1000\ cubic\ units}

<u>k = 0.216</u>

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swat32
<h2>Answer:</h2>

The value of y is 8.4375

<h2>Step-by-step explanation:</h2><h3>Known :</h3>
  • y = 7.5
  • x = 2

<h3>Asked :</h3>
  • The value of y when x is 2.25

<h3>Solution :</h3>

2/7.5 = 2.25/y

Do a cross multiplication,

2/7.5 = 2.25/y

=> 20/75 = 2.25/y

=> 75 . 2.25 = 20y

=> 168.75 = 20y

Reverse the equation,

168.75 = 20y

=> 20y = 168.75

Find the value of y,

20y = 168.75

=> y = 8.4375

<h3>Conclusion :</h3>

y = 8.4375

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2 years ago
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2 years ago
Let v = (v1, v2) be a vector in R2. Show that (v2, −v1) is orthogonal to v, and use this fact to find two unit vectors orthogona
andrey2020 [161]

Answer:

a. v.v' = v₁v₂ -  v₁v₂ = 0 b.  (20, -21)/29 and  (-20,21)/29

Step-by-step explanation:

a. For two vectors a, b to be orthogonal, their dot product is zero. That is a.b = 0.

Given v = (v₁, v₂) = v₁i + v₂j and v' =  (v₂, -v₁) = v₂i - v₁j, we need to show that v.v' = 0

So, v.v' = (v₁i + v₂j).(v₂i - v₁j)

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= v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j

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So, v.v' = v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j  

= v₁v₂ × 1 - v₁v₁ × 0 + v₂v₂ × 0 - v₂v₁ × 1

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=  v₁v₂ -  v₁v₂ = 0

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So the first unit vector is thus a = v'/║v'║ = (20, -21)/√[20² + (-21)²] = (20, -21)/√[400 + 441] = (20, -21)/√841 = (20, -21)/29.

A unit vector perpendicular to a and parallel to v is b = (-21, -20)/29. Another unit vector perpendicular to b, parallel to a and perpendicular to v is thus a' = (-20,-(-21))/29 = (-20,21)/29

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The total distance would be 2700.

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Suppose the whole distance is X when time is 0, and after flying for 6 seconds he now is 2430 meter away. It means that he must have covered the distance of X-2430=270.

Finding for X, we gets the full initial distance, when time was 0.

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