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Katen [24]
3 years ago
8

Write each expression as a multiple of a power of 100.04

Mathematics
1 answer:
Anestetic [448]3 years ago
6 0

Answer:

<h2>4 x 10⁻²</h2>

Step-by-step explanation:

The decimal place moves by places to the left, thus 10^-2 multiplied by 4.

I'm always happy to help :)

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An anemometer is a device used to measure wind speed.
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3.32ft

Step-by-step explanation:

The wire and the poles attached to the ground form a right triangle with the length of the wire being the hypotenuse.

Using Pythagoras Theorem:

Hypotenuse²=Adjacent²+Opposite²

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x²=36-25

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x=√11=3.32 ft.

The wires are attached 3.32 ft from the base of the pole on the ground

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3 years ago
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1. The linear equation y = 1/4x tells us that this line is going to be more vertical or horizontal? Explain.
KonstantinChe [14]
Its going more horizontal because the slope has you go up 1 and right 4, meaning you are going right more than you are going up
5 0
3 years ago
Can somebody please help me
olasank [31]

Answer:

70

Step-by-step explanation:

Complementary angles equal 90 degrees

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5 0
2 years ago
Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

  • J(2;5); K(1;1)

             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0
3 years ago
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