<span>3x^2 + 4x + 8 + 2x^2 - 6x + 3 to give result as 9x^2 -2x - 5
</span>3x^2 + 4x + 8 + 2x^2 - 6x + 3
= 5x^2 - 2x + 11
so
9x^2 -2x - 5 - (5x^2 - 2x + 11)
= 9x^2 -2x - 5 - 5x^2 + 2x - 11
= 4x^2 -16
answer
expression (4x^2 -16) must be added to the sum of (3x^2 + 4x + 8) and (2x^2 - 6x + 3) to give the result as (9x^2 - 2x - 5)
3x+2=x+8
Slandered Form
2x-6=0
Factorizations
2(x-3)=0
Solutions
x=6/2=3 (6 divided by 2 = 3)
Answer:
It is true that the quotient of two integers is always a rational number. This is because a rational number is any number that can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q.
Answer:
Area = 9π sq. m.
Step-by-step explanation:
C = πd
6π = πd
d = 6
r = 3
A = π
= π
= 9π sq. m.
