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3 years ago

13

On a Saturday, a library checked out 52 books. If 24 of the books were fiction , what is the ratio if non-fiction books to ficti

on books checked out

2 answers:

Elodia [21]3 years ago

6 0

28:52 or 28 to 52. Subtract the fiction from the nonfiction to get 28, then compare it, the non-fiction first, to the whole number of books.

vekshin13 years ago

4 0

I would guess 28 to 24

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Answer:

The Ration of length 2.0 meters to the length 1.2 meters = 5 : 3

Step-by-step explanation:

The given two length are 2.0 m and 1.2 m

Length L1 = 2.0 m And

Length L2 = 1.2 m

SO, The ratio of L1 : L2 = $\frac{2.0}{1.2}$

Or, The ratio of L1 : L2 = $\frac{20}{12}$

∴ The ratio of L1 : L2 = $\frac{5}{3}$

Hence The ratio of L1 : L2 is 5 : 3 Answer

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3 years ago

A survey was conducted of 42 students who take math, Eng lish, or history. In the survey, 15 students said they take math and hi

strojnjashka [21]

Answer:

16 students take only English or only Math.

Step-by-step explanation:

We can solve this problem by treating these values as sets, and building the Venn Diagram.

I am going to say that:

A is the number of students who take Math.

B is the number of students who take English.

C is the number of students who take History.

We have that:

$A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)$

In which a is the number of students that only take Math, $A \cap B$ is the number of students who take both Math and English, $A \cap C$ is the number of students that take both Math and History, and $A \cap B \cap C$ is the number of students that take all these classes.

By the same logic, we have:

$B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)$

$C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

This diagram has the following subsets:

$a,b,c,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)$

There were 42 students suveyed. This means that:

$a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 42$

We start finding the values from the intersection of three sets.

12 students said they take math, English, and history. This means that:

$A \cap B \cap C = 12$

18 students said they take English and history. This also takes into account those who take math, english and history. So:

$(B \cap C) + (A \cap B \cap C) = 18$

$B \cap C = 6$

17 students said they take math and English.

$(A \cap B) + (A \cap B \cap C) = 17$

$A \cap B = 5$

15 students said they take math and history

$(A \cap C) + (A \cap B \cap C) = 15$

$A \cap C = 3$

2 students said they only take history.

$c = 2$

How many students take only English or only math?

This is a + b, that we can find by the following formula:

$a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 42$

$a + b + 2 + 5 + 3 + 6 + 12 = 42$

$a + b = 16$

16 students take only English or only Math.

4 0

3 years ago