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3 years ago

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On a Saturday, a library checked out 52 books. If 24 of the books were fiction , what is the ratio if non-fiction books to ficti

on books checked out

2 answers:

Elodia [21]3 years ago

6 0

28:52 or 28 to 52. Subtract the fiction from the nonfiction to get 28, then compare it, the non-fiction first, to the whole number of books.

vekshin13 years ago

4 0

I would guess 28 to 24

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Andrew buys books and videos in a store. He uses the expression 4b + 8v to find the cost of what he is buying, where b is the nu

7nadin3 [17]

Answer:

68

Step-by-step explanation:

1) Plug In (when you plug in you replace the defined variable with the number given. usually you have to find the numbers to plug in but since they're already given to you you just plug them in.) 4(3) + 8(7)=T T= total cost

2) Multiply 4*3=12 8*7=56

3) Add 12+56=68

4) <u>T=68</u>

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3 years ago

The functions f (x) = 1/2x-3 and g(x) = -2x+ 2 intersect<br> at x = -2. True or false?

Norma-Jean [14]

9514 1404 393

Answer:

False

Step-by-step explanation:

f(-2) = (1/2)(-2) -3 = -1 -3 = -4

g(-2) = -2(-2) +2 = 4 +2 = 6

The function values are not the same at x=-2, so the graphs do not intersect there.

__

The graphs intersect at x=2.

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3 years ago

<img src="https://tex.z-dn.net/?f=%20-%20x%20-%202%20%5Cdiv%20x%28x%20%7B%7D%5E%7B2%7D%20%20-%204%29" id="TexFormula1" title=" -

saw5 [17]

Answer:

Step-by-step explanation:

Hello,

First of all we will take any real number x different from 0, -2, +2 as dividing by 0 is not allowed and then we can write

$\dfrac{( - x - 2)}{x(x^2 - 4)}=-\dfrac{x+2}{x(x-2)(x+2)}=\large \boxed{ -\dfrac{1}{x(x-2)}}$

because we know that

$x^2-4=x^2-2^2=(x-2)(x+2)$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

8 0

3 years ago

What is the total resistance of a parallel circuit that has two loads? Load one has a resistance of 10 ohms. Load two has a resi

Romashka-Z-Leto [24]

Answer:

The total resistance is $7.0588\Omega$

Step-by-step explanation:

Attached please find the circuit diagram. The circuit is composed by a voltage source and two resistors connected in parallel: $R_1=10\Omega$ and $R_2=24\Omega$ .

First step: find the total current

For finding the current that the voltage source can provide, you must find the current consumed by each load and then add both. To do that, take first into account that the voltage is the same for both resistors ( $R_1$ and $R_2$ ).

$I_{R_1}=\frac{V_S}{R_1}$
$I_{R_2}=\frac{V_S}{R_2}$

The total current is:

$I_{TOTAL}=I_{R_1}+I_{R_2}=\frac{V_S}{R_1}+\frac{V_S}{R_2}=\frac{R_2\cdot V_S+R_1\cdot V_S}{R_1\cdot R_2}$

$I_{TOTAL}=V_S\cdot \frac{R_1+R_2}{R_1\cdot R_2}$

Now, the total resistance ( $R_{TOTAL}$ ) would be the voltage divided by the total current:

$R_{TOTAL}=\frac{V_S}{I_{TOTAL}}$

If you replace $I_{TOTAL}$ by the expression obtained previously, the total resistance would be:

$R_{TOTAL}=\frac{V_S}{V_S\cdot \frac{R_1+R_2}{R_1\cdot R_2}}$

After simplifying the terms you should get:

$R_{TOTAL}=\frac{R_1\cdot R_2}{R_1 + R_2}}$

Now, you must replace the values of the resistors:

$R_{TOTAL}=\frac{(10\Omega )\cdot (24\Omega)}{10\Omega + 24\Omega}}=\frac{120}{17}\Omega=7.0588\Omega$

Thus, the total resistance is $7.0588\Omega$

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4 years ago

Mary has $6.00 in nickels, dimes, and quarters. if she has twice as many dimes as quarters and eighty-seven more nickels than di

Novosadov [1.4K]

93 nickels 6 dimes 3 quarters

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3 years ago