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tiny-mole [99]
3 years ago
9

2.5 ( y + ⅖ ) = -13 im really bad at math someone pls help

Mathematics
1 answer:
My name is Ann [436]3 years ago
5 0

Answer:

-5.6

Step-by-step explanation:

first distribute the 2.5

also convert the 2/5 to decimal (0.4) because it's hard to work with both decimal and fraction

2.5y + 2.5*0.4 = -13

2.5y +1 = -13

y = -14/2.5 = -5.6

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HELP FAST PLEASE
yan [13]

Answer:

(x - 3, y + 6)

Step-by-step explanation:

Point K starts as (1, -3)

Point K after the translation becomes (-2, 3)

The x-coordinate goes from 1 to -2. That is a change of -3 in x, or x becomes x - 3.

The y-coordinate goes from -3 to 3. That is a change of +6 in y, or y becomes y + 6.

Answer: (x - 3, y + 6)

6 0
3 years ago
Find the composite area of the polygon
KIM [24]

Answer:

Obtaining the area or perimeter is the easiest and basic skills in geometry, however, when combining several plane figures, composite shapes are formed, which can include: squares, circles, triangles, rectangles, trapezoids, etc.

To obtain the area or perimeter of this type of figures should analyze the figure and follow these steps:

STEP I

♦ Must identify which figures form the total.

STEP II

 

♦ Analyze if there are parts of the figures that you will not need, for example the sides that join two or more figures.

STEP III

 

♦ Obtain separately the areas and perimeters of each figure

STEP IV

♦Add the obtained in each figure.

Hope it helps you!

Step-by-step explanation:

5 0
3 years ago
Find the twenty-fifth term of an= (-1)^n
oksano4ka [1.4K]

Answer: -1

Step-by-step explanation: plug in 25 into (-1)^n

4 0
3 years ago
Find the vertex, focus, directrix, and focal width of the parabola. (5 points)
Anarel [89]

\bf \textit{vertical parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h,k+p)}\qquad \stackrel{directrix}{y=k-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\cap}\qquad \stackrel{"p"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf -\cfrac{1}{20}x^2=y\implies \cfrac{x^2}{-20}=y\implies x^2=-20y\implies (x-0)^2=-20(y-0) \\\\\\ (x-\stackrel{h}{0})^2=4(\stackrel{p}{-5})(y-\stackrel{k}{0})

something noteworthy is that the squared variable is the "x", thus the parabola is a vertical one, the "p" value is negative, so is opening downwards, and the h,k is pretty much the origin,

vertex is at (0,0)

the focus point is "p" or 5 units down from there, namely at (0, -5)

the directrix is "p" units on the opposite direction, up, namely at y = 5

the focal width, well, |4p| is pretty much the focal width, in this  case, is simply yeap, you guessed it, 20.

8 0
3 years ago
Please help with this
N76 [4]
VWX\cong KLJ means that the triangles are congruent, that is exactly identical.

The order of letters is very important. Form the given congruence we can write the following ratio:

\frac{VW}{KL} = \frac{WX}{LJ} = \frac{VX}{KJ} =1

(notice that we do not mix the order: the first 2 letters of VWX are compared to the first 2 letters of KLJ and so on)

the ratio is one because the corresponding sides are equal.

\frac{VW}{KL}=1\\\\ \frac{2z-1}{z+2}=1\\\\2z-1=z+2\\\\2z-z=2+1\\\\z=3

|VW|=2z-1=2.3-1=6-1=5


Answer: 5 units


8 0
3 years ago
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