Answer:
The answer to the question is
It take for the golf ball hit on Mars to reach the ground 8.284 s longer.
Step-by-step explanation:
To Solve the question, we note that the equation of motion is given to us as
h = -1.9·t² + 26·t
Therefore the height
We compare the above equation with the equation of of motion
S = ut - 0.5×g×t² where u = initial velocity = 26 m/s and - 0.5×g = -1.9
Therefore the acceleration due to gravity om mars = -1.9/-0.5 = 3.8 m/s²
We now have the time taken to maximum height given by
v = u - g·t where v = 0 at maximum height
We therefore have u = g·t → 26 = 3.8×t or t = 26/3.8 = 6.84 seconds
The time taken for ball to hit the ground is 2 × the time to reach maximum height = 2 × 6.84 = 13.684 s
The time longer it takes for the ball on Mars to complete the path up to maximum height and down again is 13.684 s - 5.4 s = 8.284 s.
Answer:
y=6/5x-2
Step-by-step explanation:
y=mx+C
Y=6/5X+C
4=6+c
c=-2
y=6/5x-2
Answer:16
Step-by-step explanation:
Add each side togeather
Answer:
Any figure?
Step-by-step explanation:
