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Bogdan [553]
3 years ago
13

Find the negative square root of twenty

Mathematics
1 answer:
nataly862011 [7]3 years ago
6 0
I'm sorry but the answer to your question is NaN.Check your calculator and u will see
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Answer:what kind of math u doing

Step-by-step explanation:

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❗️❗️❗️Find the length of side x in simplest radical form with a rational denominator.❗️❗️❗️
tiny-mole [99]

Answer:

x=\frac{\sqrt{14} }{2}

Step-by-step explanation:

Notice that you are given an isosceles right-angle triangle to solve, since each of its two acute angles measures 45^o. Then such means that the sides opposite to these acute angles (the so called "legs" of this right angle triangle) must also be of the same length (x).

We can then use the Pythagorean theorem that relates the square of the hypotenuse to the addition of the squares of the triangles legs:

(\sqrt{7})^2=x^2+x^2\\7=2\,x^2\\x^2=\frac{7}{2} \\x=+/-\sqrt{\frac{7}{2}} \\x=+/-\frac{\sqrt{14} }{2}

We use just the positive root, since we are looking for an actual length. then, the requested side is:

x=\frac{\sqrt{14} }{2}

6 0
3 years ago
A rectangle is constructed with its base on theâ x-axis and two of its vertices on the parabola yequals=2525minusâxsquared2. wha
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You should have drawn1 - x-axis and y-axis in light pencil.2 - graphed a down-facing parabola with the top of the frown on the y-axis at y = 2.  It should be crossing the x-axis at ±√2.  This should be in dark pencil or another color.3 - In dark pencil or a completely new color, draw a rectangle with one of the horizontal sides sitting on top of the x-axis and the other horizontal side touching the parabola at each of the top corners of the rectangle. The rectangle will have half of its base in the positive x-axis and the other half on the negative x-axis.  It should be split right down the middle by the y-axis.  So each half of the base we will say is "x" units long.  So the whole base is 2x units long (the x units to the right of the y-axis, and the x units to the left of the y-axis)  I so wish I could draw you this picture...   In the vertical direction, both vertical edges are the same length and we will call that y.   The area that we want to maximize has a width 2x long, and a height of y tall. So A = 2xy     This is the equation we want to maximize (take derivative and set it = 0), we call it the "primary equation", but we need it in one variable. This is where the "secondary equation" comes in.  We need to find a way to change the area formula to all x's or all y's. Since it is constrained to having its height limited by the parabola, we could use the fact that y=2 - x2 to make the area formula in only x's.   Substitute in place of the "y", "2 - x2" into the area formula. A = 2xy = 2x(2 - x2)   then simplify A = 4x - 2x3     NOW you are ready to take the deriv and set it = 0 dA/dx = 4 - 6x2       0 = 4 - 6x2   6x2 = 4    x2 = 4/6 or 2/3 So x = ±√(2/3) Width remember was 2x.   So the width is 2[√(2/3)]Height is y which is 2 - x2 = 2 - 2/3  =4/3
6 0
3 years ago
A salesman has a base salary $2600 per month and makes 3 commission on each unit sold. If his total annual compensation is $48,0
nevsk [136]

Answer:

Each unit cost $800

Step-by-step explanation:

Annual compensation = $48,000

Annual number of units sold = 2000

Commission on each item sold = 3%

Compensation for 2000 units = $48,000

Compensation for 1 unit = $48,000/2000 = $24

Cost of one unit = compensation for one unit ÷ commission on one unit = $24 ÷ 3% = $24 ÷ 0.03 = $800

8 0
3 years ago
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