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Crazy boy [7]
3 years ago
14

С

Chemistry
1 answer:
algol [13]3 years ago
6 0

The percent composition  of this compound :

Mg = 72.182%

N = 27.818%

<h3> Further explanation </h3>

Given

9.03 g  Mg

3.48 g  N

Required

The percent composition

Solution

Proust stated the Comparative Law that compounds are formed from elements with the same Mass Comparison so that the compound has a fixed composition of elements

Total mass of the compound :

= 9.03 g + 3.48 g

= 12.51 g

The percent composition :

Mg : 9.03/ 12.51 g x 100% = 72.182%

N : 3.48 / 12.51 g x 100% = 27.818%

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Answer:

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3 years ago
What is the freezing point (°C) of a solution prepared by dissolving 11.3 g of Ca(NO3)2 (formula weight = 164 g/mol) in 115 g of
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Answer:

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Explanation:

From the given information:

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molality = \dfrac{mole \ of \ Ca(NO_3)_2}{kg \ of \  water}

molality = \dfrac{\dfrac{mass \ of \  \ Ca(NO_3)_2}{molar \  mass of \ Ca(NO_3)_2} }{kg \ of \  water}

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The freezing point (°C) of a solution can be prepared by using the formula:

\Delta T = iK_fm

\Delta T =3 \times (1.86 \ ^0C/m) \times (0.599 \ m)

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\Delta T = the freezing point of water - freezing point of the solution

3.34° C = 0° C -  freezing point of the solution

freezing point  (°C) of the solution =  0° C - 3.34° C

freezing point   (°C) of the solution =  - 3.34° C

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