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WINSTONCH [101]
4 years ago
9

A single serving bag of snack chips contains 65.0 Cal. Assuming that all of the energy from eating these chips goes toward keepi

ng your heart beating, how many hours can these chips sustain a heartbeat of 73 beats per minute?
Chemistry
1 answer:
AveGali [126]4 years ago
5 0

Answer:

= 62.1 hours

Explanation:

Energy provide by the serving is 65 cal

= 65 cal  × 4.184 Kj = 271.96 kJ

271.96 KJ = 271960 J

Energy required for 1minute of energy

= 73 x 1

= 73 J/min

So, 271960 joules will be required for 271960 heart beat

Minutes = 271960 / 73

= 3593.94 minutes  

Time in hours = 3725.429 / 60

= 62.1 hours

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248 miles

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3 years ago
Can someone explain this to me, please?
zimovet [89]

Answer:

Isotopes have same atomic numbers, no. of protons and no. of electrons. Only their no. of neutrons and atomic mass are changed.

<u>Na - 24:</u>

Atomic Mass = 24

Atomic No. = 11

Hence,

No. of protons in Na-24 = 11

No. of neutrons = Atomic Mass - Atomic Number

No. of neutrons = 24 - 11

No. of neutrons = 13

Atomic Number = 11

\rule[225]{225}{2}

Hope this helped!

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Determine the standard enthalpy of formation in kJ/mol for NO given the following information about the formation of NO2 under s
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Answer:

90.3 kJ/mol

Explanation:

Let's consider the following thermochemical equation.

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We can find the standard enthalpy of formation for NO using the following expression.

∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g)) - 1 mol × ΔH°f(O₂(g))

∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g)) - 1 mol × 0 kJ/mol

∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g))

ΔH°f(NO(g)) = (2 mol × ΔH°f(NO₂(g)) - ∆H°rxn) / 2 mol

ΔH°f(NO(g)) = (2 mol × 33.2 kJ/mol + 114.2 kJ) / 2 mol

ΔH°f(NO(g)) = 90.3 kJ/mol

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