What is the area of a triangle with vertices at (−4, 1) , (−7, 5) , and (0, 1) ? Enter your answer in the box. ___units²
2 answers:
Check the picture below.
you can pretty much count those lengths off the grid.
recall that A = 1/2 bh.
you can pretty much count those lengths off the grid.
recall that A = 1/2 bh.
Since area (a) of a triangle = 1/2 (b)*(h), our base will be the horizontal distance between (-4, 1) and (0, 1), which is just the absolute (positive) value of the difference between the x-values:
So b = 4 units
Now the height is the vertical distance from top to bottom, or the absolute value of the difference between y-values:
So h = 4
Now a = 1/2 (b)(h) = 1/2 (4)(4) = 1/2 (16) = 8 units squared...
So b = 4 units
Now the height is the vertical distance from top to bottom, or the absolute value of the difference between y-values:
So h = 4
Now a = 1/2 (b)(h) = 1/2 (4)(4) = 1/2 (16) = 8 units squared...
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Answer with explanation:
<u>Part A: </u>
One solution.
The number of points of intersection represents the number of solutions. Since the two lines only intersect at one point, there is only one solution.
<u>Part B:</u>
(3, 4)
The point(s) of intersection marks the solution(s) to the lines. Since lines A and B intersect at the point (3, 4), the solution to the equation of their lines is (3, 4), or , as coordinates are written as (x, y).
Answer:
x = -7
Step-by-step explanation:
To find the value of x, you need to set up a proportion:
=
Then cross multiply:
15x - 15 = 18x + 36
Then subtract 15x from both sides:
-15 = 3x + 36
Subtract 36 from both sides:
-51 = 3x
Finally, divide both sides by 3:
x = -7