Through 1-3 There should be a line that goes from (0,0) to (3,15) as they did work for three hours. The rest seems fine.
Answer:
y = -x/3 + 6
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
Standard Form: Ax + By = C
Slope-Intercept Form: y = mx + b
- m - slope
- b - y-intercept
Step-by-step explanation:
<u>Step 1: Define</u>
Standard Form: x + 3y = 18
<u>Step 2: Rewrite</u>
<em>Find slope-intercept form</em>
- Subtract <em>x</em> on both sides: 3y = -x + 18
- Divide 3 on both sides: y = -x/3 + 6
- The Midpoint of AB is (1,0).
Given that:
- In line AB, where the coordinates of A is (3,1) and coordinates of B is (-1,-1).
To find:
So, according the question
We know that,
The midpoint M of a line segment AB with endpoints A (x₁, y₁) and B (x₂, y₂) has the coordinates M (
).
Now from question,
We know that the the coordinates of A is (3,1) and coordinates of B is (-1,-1) of line AB.
So, we can say that
A is (3,1) or x₁ = 3 and y₁ = 1.
B (-1,-1) or x₂ = -1 and y₂ = -1.
∵ The coordinates of midpoint M (X,Y)
X = 
= 
= 2/2
X = 1.
And
Y = 
= 
= 0/2
Y = 0.
So, the midpoint of line AB is M (1,0)
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I mean, this isn't a question but its true?