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Vadim26 [7]
3 years ago
15

Suppose r = 9 + 3s. What is r, if s = 6?

Mathematics
2 answers:
topjm [15]3 years ago
4 0
Plug in 6 for everywhere s is in the equation
r = 9 + 3s
r = 9 + 3(6)
r = 9 + 18
r = 27
27 is the answer!
hichkok12 [17]3 years ago
3 0
I believe that r = 27
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The function f(x) = x] is graphed over the interval [-6, 3]. Which translation of the graph has the domain (-3, 6]? 0 A. g(x) =
bezimeni [28]

An interval graph in graphical theory is indeed an undirected graph formed by an interval set just on true line, with a top for every interval as well as an edge between vertex v to intersections. Graph intervals and these graphs are chordal graphs and graphs that are perfect, and the further discussion can be defined as follows:

Given:

\bold{function\ f(x) = |x|}

\bold{Interval \ \[-6, 3\]}

To find:

Domain=?

Solution:

The \bold{function\ f(x) = |x|} is a graphic over the[-6,3] interval.

A<em><u> graph of the domain</u></em> [-3,6 ] is indicated mostly by the <em><u>transformation </u></em>that <em><u>horizontal shifts</u></em> to combat (h(x)=f(x-3)).

\to \bold{h(x) =f(x-3)}

            =|x-3|

Therefore, the final answer is "Option (D)".

  • Please find the complete question and a rule in the attachment file.

Learn more:

brainly.com/question/24161708

8 0
2 years ago
Simplify the expression using trigonometric identities: sec (–θ) – cos θ.
ololo11 [35]

Answer:

sin θ . tan θ

Step-by-step explanation:

Note : -

sec ( - θ ) = sec θ

Formula / Identity : -

sec θ = 1 / cos θ

sec ( - θ ) - cos θ

= [ 1 / cos θ ] - cos θ

{ LCM = cos θ }

= [ 1 / cos θ ] - [ cos²θ / cos θ ]

= [ 1 - cos²θ ] / cos θ

{ 1 - cos²θ = sin²θ }

= sin²θ / cos θ

{ sin²θ = sin θ . sin θ }

= sin θ . sin θ / cos θ

{ sin θ / cos θ = tan θ }

= sin θ . tan θ

Hence, simplified.

4 0
2 years ago
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