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Marat540 [252]
3 years ago
9

How do i find the square root of a number?

Mathematics
1 answer:
elena-s [515]3 years ago
8 0
The square route is what times itself can get you that number such as 64, 8*8= 64, 8 is the square route.
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I need help with this one
Tomtit [17]

Answer:

mean > median

Step-by-step explanation:

The graph is skewed right since the data is to the left.  

When the graph is skewed right, the median is usually less than the mean

This means the mean > median

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A line segment has the endpoints (2 -5) and (-1 -1) what is its slope?
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I believe,
since... slope = (y2-y1)/(x2-x1)
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A class of 25 students is making necklaces. The necklaces each have 30 beads. How many beads are needed for each student to make
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Step-by-step explanation:

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What must be true for lines a and b to be parallel lines? Select four options.
zzz [600]

The question is missing figure and the options. So, the figure is attached alongwith the options

Answer:

Correct options: (1), (2) , (7) and (8)

Step-by-step explanation:

Given:

Lines a and b are parallel.

Consider a║b  and 'd' be a transversal  then,

Statements                                    Reasons

1. ∠BXZ = ∠AZP = 58°                Corresponding angles are equal

∴ m∠2 = 58°

2. ∠BYC = ∠XYZ = (4x-10)° Vertically opposite angles are equal

Now, consider a║b and 'c' be a transversal then,

Statements                             Reasons

1. ∠XYZ = ∠QZU = (4x-10)°  Corresponding angles are equal

∴ m∠1 =  (4x-10)°

2.∠PZA + ∠PZQ + ∠QZU = 180° Sum of angles on a straight line is 180°.

3. 58\° +(3x-1)\°+(4x-10)\° = 180\°      Substitution property

4. 47\° + 7x= 180\°                   Combining like terms

5. 7x=180\°-47\°                         Subtraction property of equality

   ∴ 7x = 133\°

6. x = 19\°                                 Division property of equality

Plug in x = 19\ in\ (3x-1)\°\ and\ (4x-10)\°, we get

(3x-1)\° = (3(19)-1)\° = 56°

(4x-10)\° = (4(19)-10)\° = 66°

So, (3x-1)\° \ne (4x-10)\°

Hence, options (1), (2) , (7) and (8) are correct.

4 0
3 years ago
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