What is the amplitude ? How do I find it? do I add 7.7 to (-6.7) then divide? Thank you in advance

Mathematics

1 answer:

labwork [276]2 years ago

3 0

Answer:

7.2

Step-by-step explanation:

The amplitude is half the difference between the maximum and the minimum.

A = (7.7 − (-6.7)) / 2

A = 7.2

You might be interested in

Help: Simplifying inside parenthesis first

Ne4ueva [31]

Answer:

4th one

Step-by-step explanation:

a^-2 goes down and become a^2 and

${a}^{2} \times {a}^{2} = {a}^{4}$

b^-1 goes up and become b

${b}^{2} \times {b}^{1} = {b}^{3}$

that why answer is 4th...mark me brainliest please

3 0

2 years ago

Write an equation of a parabola that passes through the point (2,4) with vertex (-1,-1) in vertex form.

quester [9]

An applicable equation of a vertical parabola in vertex form is:

y-k = a(x-h)^2

Let x=2, y=4, h=-1 and k=-1, where (h,k) is the vertex. Then,

4-(-1) = a(2-[-1])^2, which becomes 5 = a(9). Therefore, a = 5/9, and the
equation of the parabola is

y+1 = (5/9)(x+1)

8 0

2 years ago

There are 250 wolves in a national park. the wolf population is increasing at a rate of 16% per year. write an exponential model

Helga [31]

$\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &250\\ r=rate\to 16\%\to \frac{16}{100}\dotfill &0.16\\ t=\textit{elapsed time} \end{cases} \\\\\\ A=250(1 + 0.16)^{t}\implies A=250(1.16)^t \\\\[-0.35em] ~\dotfill$

$A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\dotfill &1000\\ P=\textit{initial amount}\dotfill &250\\ r=rate\to 16\%\to \frac{16}{100}\dotfill &0.16\\ t=\textit{elapsed time} \end{cases} \\\\\\ 1000=250(1.16)^t\implies \cfrac{1000}{250}=1.16^t\implies 4=1.16^t \\\\\\ \log(4)=\log(1.16^t)\implies \log(4)=t\log(1.16) \\\\\\ \cfrac{\log(4)}{\log(1.16)}=t\implies \stackrel{\textit{about 9 years and 4 months}}{9.34\approx t}$