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Alex
3 years ago
6

What is the nominal annual interest rate

Mathematics
2 answers:
aivan3 [116]3 years ago
6 0

Answer:

the nominal interest rate is the periodic interest rate.

pychu [463]3 years ago
4 0

it  is the periodic interest rate times the number of periods per year.

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Solve <br> Y/2 +22=38 for .<br><br> do u mind answering for some points?
Rasek [7]

Answer:

Step-by-step explanation:

Y = 32

3 0
3 years ago
Help me please??????
Natasha2012 [34]

Answer:

y=-3x-3

Step-by-step explanation:

To get a perpendicular line you take the negative reciprocal of the slope, so in this case it would equal -3. Now use point-slope form to get your equation. Point slope form says that y-y1=m(x-x1) where m is your slope and x1 and y1 are the points that the graph passes through. So in this case x1=-3, y1=6, and m=-3. This gives you the equation y-6=-3(x+3). Distribute to y-6=-3x-9, and finally add 6 to both sides to get y=-3x-3

5 0
3 years ago
Let x = 1 and y= -2, which expression has a negative value?
Nonamiya [84]

Answer:

The following expressions become negative:

  • 1) x+y = 1+(-2) = -1
  • 3) x times y = xy = (1)(-2) = -2
  • 4) x divided by y = x/y = 1/-2 = -2

Step-by-step explanation:

Given

  • x = 1
  • y = -2

Computing by substituting x = 1, and y = -2

1) x+y = 1+(-2) = -1

2) x - y = 1 - (-2) = 1+2 = 3

3) x times y = xy = (1)(-2) = -2

4) x divided by y = x/y = 1/-2 = -2

It is clear from the above calculations that when we put x = 1, and y=-2 then the expressions (x+y), (x times y), and (x divided by y) become negative.

Therefore, the following expressions become negative:

  • 1) x+y = 1+(-2) = -1
  • 3) x times y = xy = (1)(-2) = -2
  • 4) x divided by y = x/y = 1/-2 = -2
4 0
3 years ago
How to check if a binomial is a difference of squares ?
tiny-mole [99]
This I my explanation for this question if it is helpful your welcome

4 0
3 years ago
HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME
Kryger [21]

Answer:

1)

Given the triangle RST with Coordinates  R(2,1), S(2, -2) and T(-1 , -2).

A dilation is a transformation which produces an image that is the same shape as original one, but is different size.  

Since, the scale factor \frac{5}{3} is greater than 1, the image is enlargement or a stretch.  

Now, draw the dilation image of the triangle RST with center (2,-2) and scale factor \frac{5}{3}

Since, the center of dilation at S(2,-2) is not at the origin, so the point S and its image S{}' are same.

Now, the distances from the center of the dilation at point S to the other points R and T.  

The dilation image will be\frac{5}{3} of each of these distances,

SR=3, so S{}'R{}'=5 ;


ST=3, so S{}'T{}'=5  

Now, draw the image of RST i.e R'S'T'

Since, RT=3\sqrt{2} [By using hypotenuse of right angle triangle] and R{}'T{}'=5\sqrt{2}.


2)

(a)

Disagree with the given statement.

Side Angle Side postulate (SAS) states that:

If two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle then these two triangles are congruent.

Given: B is the midpoint of \overline{AC} i.e \overline{AB}\cong \overline{BC}

In the triangle ABD and triangle CBD, we have

\overline{AB}\cong \overline{BC}   (SIDE)            [Given]

\overline{BD}\cong \overline{BD}   (SIDE)            [Reflexive post]

Since, there is no included angle in these triangles.

∴ \Delta ABD is not congruent to \Delta CBD .

Therefore, these triangles does not follow the SAS congruence postulates.

(b)

SSS(SIDE-SIDE-SIDE) states that if three sides of one triangle are congruent to three sides of another triangle, then the triangles are congruent.

Since it is also given that  \overline{AD}\cong \overline{CD}.

therefore, in the triangle ABD and triangle CBD, we have

\overline{AB}\cong \overline{BC}   (SIDE)            [Given]

\overline{AD}\cong \overline{CD}   (SIDE)           [Given]

\overline{BD}\cong \overline{BD}   (SIDE)            [Reflexive post]

therefore by, SSS postulates \Delta ABD\cong \Delta CBD.

3)

Given that:  \angle1=\angle 3 are vertical angles, as they are formed by intersecting lines.

Therefore

, by the definition of linear pairs

\angle 1 and \angle 2 and \angle 3  and \angle 2 are linear pair.

By linear pair theorem, \angle 1 and \angle 2   are supplementary, \angle 2 and \angle 3  are supplementary.

m\angle1+m\angle 2=180^{\circ}

m\angle2+m\angle 3=180^{\circ}

Equate the above expressions:

m\angle 1+m\angle 2=m\angle 2+m\angle 3

Subtract the angle 2 from both sides in the above expressions

∴m\angle 1=m\angle 3

By Congruent Supplement theorem: If two angles are supplements of the same angle, then the two angles are congruent.


therefore, \angle 1\cong \angle 3.















3 0
3 years ago
Read 2 more answers
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